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In the redox reaction between iodine (I₂) and thiosulfate (S₂O₃²⁻), the half-reaction for iodine is the reduction of I₂ to iodide (I⁻). The half-reaction can be represented as:

[ \text{I}_2 + 2 \text{e}^- \rightarrow 2 \text{I}^- ]

For thiosulfate, it acts as a reducing agent and is oxidized to sulfate (SO₄²⁻), but the focus here is on the reduction of iodine.

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7mo ago

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