The chemical reaction of photosynthesis is:
6 CO2 + 6 H2O = C6H12O6 + 6 O2
To calculate the cellular respiration rate in moles of glucose per minute, you need to convert the volume of CO2 produced into moles using the ideal gas law. Then, you can use the stoichiometry of the cellular respiration reaction to relate the moles of CO2 produced to moles of glucose consumed. Once you have both values, you can determine the rate of glucose consumption per minute.
The number of moles is 2,997.
0,83moles glucose are burned.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
Because the formula for calculating moles is dividing grams by the molecular weight. The molecular weight for glucose is 180. grams to moles is also the same as milligrams to millimoles.
To calculate the cellular respiration rate in moles of glucose per minute, you need to convert the volume of CO2 produced into moles using the ideal gas law. Then, you can use the stoichiometry of the cellular respiration reaction to relate the moles of CO2 produced to moles of glucose consumed. Once you have both values, you can determine the rate of glucose consumption per minute.
One mole of glucose yields 36 moles of ATP through cellular respiration, while one mole of triglyceride (composed of lauric acid) yields 129 moles of ATP through beta oxidation and the citric acid cycle. Therefore, with 3.5 moles of each, the triglyceride will produce more energy by yielding 451.5 moles of ATP, compared to the 126 moles produced by the glucose.
2.,7 moles of glucose have 486,432 g.
The number of moles is 2,997.
0,83moles glucose are burned.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
The balanced chemical equation for the reaction is: C6H12O6 + 6O2 -> 6CO2 + 6H2O The molar mass of glucose is 180 g/mol, so 126 g of glucose is 0.7 moles. From the equation, 1 mole of glucose produces 6 moles of CO2, so 0.7 moles of glucose will produce 4.2 moles of CO2. Using the ideal gas law, at STP conditions, 4.2 moles of CO2 will occupy 94.5 liters.
4,96 x 1024 molecules of glucose is equal to 8,236 moles.
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
Glucose? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles water from one mole sugar.