Ripple voltage, in the presence of a filter capacitor, is inversely proportional to load resistance.
If the load were zero (resistance infinite), then there would be no ripple voltage. As the load increases (resistance decreases), the ripple voltage increases.
The ripple waveform will appear to be sawtooth, with the rising edge following the input AC from the diode's conductioin cycle, and with the falling edge either being linear or logarithmic, depending on load. If the load is resistive, without a regulator, the falling edge will be logarithmic. If the load is constant current, such as with a regulator, the falling edge will be linear.
The electric resistance is related to the diameter and extension of the wire submitted to a determined voltage which will determine the electric current flowing into the wire.AnswerVoltage has no effect on resistance. Resistance is determined by the length, cross-sectional area, and resistivity of a material (resistivity is affected by temperature, so temperature indirectly affect resistance).
The electrical potential energy increases as the voltage is increased. It further excites the filament in the bulb more than a lessor voltage would. Using good old ohm's law (Voltage = Current x Resistance), a larger voltage applied to a bulb at the same resistance increases the current proportionally and larger currents has the effect to cause higher temps in conductors
The terminal voltage of a self-excited shunt generator decreases with an increase in load due to an increase in voltage drop across the internal resistance of the generator. As the load current increases, the drop across the internal resistance also increases, reducing the output voltage available at the terminals. This effect is known as voltage regulation and is a common characteristic of self-excited shunt generators.
The readings on an ammeter indicate the current being drawn by a load in a circuit. This load is basically a resistance to current flow. The higher the resistance, the lower the current. The supply voltage has a direct effect on current flow. The higher the voltage applied, the higher the current will be. So the readings will vary on the ammeter according to fluctuations in load and or resistance of the circuit and the applied voltage.
Resistance in a wire causes a decrease in the flow of current. This is because resistance impedes the movement of charge carriers through the wire, leading to a reduction in the overall current. Ohm's Law (V = I x R) shows the relationship between voltage, current, and resistance in a circuit.
The effective resistance of the capacitor reduces the ripple current through the capacitor making it less effective in its function of smoothing the voltage. But if the capacitor filter is fed by a transformer and diodes, the resistance of the transformer exceeds that of the capacitor.
If the resistance is in series with the capacitor, the charge/discharge time is extended.
The dielectric material between the plates.
If the load resistance is decreased, the ripple voltage in a power supply circuit typically increases. This occurs because a lower load resistance draws more current, leading to a greater voltage drop across the output capacitor as it discharges more quickly between charging cycles. Consequently, the capacitor may not have enough time to fully charge during each cycle, resulting in a higher ripple voltage. Therefore, a decrease in load resistance generally results in increased ripple voltage.
A capacitor and a resistor has no effect on the supply voltage; however, this particular load combination will cause the load current to lead the supply voltage by some angle termed the 'phase angle'.
The magnetic field between capacitor plates does not have a significant effect on the overall performance of the capacitor. The main factors that affect a capacitor's performance are its capacitance, voltage rating, and dielectric material.
In case of a lossy capacitor, its series equivalent resistance will be large.
No.
it will improve the power factor... The angle between voltage and current will decrease depends on capacitor value.
A: It is not a bypass it is a negative feedback to effect the input voltage, Bias is when a DC voltage is applied to insure proper operation
It will decrease the voltage drop.
By Ohm's Law, current is voltage divided by resistance, so if you double both the voltage and the resistance, the current would remain the same.