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Ripple voltage, in the presence of a filter capacitor, is inversely proportional to load resistance.

If the load were zero (resistance infinite), then there would be no ripple voltage. As the load increases (resistance decreases), the ripple voltage increases.

The ripple waveform will appear to be sawtooth, with the rising edge following the input AC from the diode's conductioin cycle, and with the falling edge either being linear or logarithmic, depending on load. If the load is resistive, without a regulator, the falling edge will be logarithmic. If the load is constant current, such as with a regulator, the falling edge will be linear.

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If voltage is high will the resistance be high?

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Related Questions

What effect does the series resistance of a capacitor used in a capacitor filter have on diode current and ripple voltage compared with an ideal capacitor of no resistance?

The effective resistance of the capacitor reduces the ripple current through the capacitor making it less effective in its function of smoothing the voltage. But if the capacitor filter is fed by a transformer and diodes, the resistance of the transformer exceeds that of the capacitor.


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The dielectric material between the plates.


Ask effect on ripple voltage if load resistance is decreased?

If the load resistance is decreased, the ripple voltage in a power supply circuit typically increases. This occurs because a lower load resistance draws more current, leading to a greater voltage drop across the output capacitor as it discharges more quickly between charging cycles. Consequently, the capacitor may not have enough time to fully charge during each cycle, resulting in a higher ripple voltage. Therefore, a decrease in load resistance generally results in increased ripple voltage.


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In case of a lossy capacitor, its series equivalent resistance will be large.


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