If you think to the electron configuration of magnesium this is: [Ne]3s2.
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
Helium (He) is the element that has a negative electron affinity. This means that it is less likely to gain an electron compared to other elements listed (Kr, O, Ca, and Mg) which have positive electron affinities.
Beryllium (Be) has a greater shielding effect than magnesium (Mg) because it has fewer electron shells. In Be, the single electron in its outer shell experiences less shielding from the inner electrons, while in Mg, the additional electron shells introduce more inner electrons that can shield the outer electrons more effectively. Therefore, the overall shielding effect is greater in Mg due to its larger number of electron shells.
The noble gas that has the same electron configuration as magnesium ion (Mg²⁺) is neon (Ne). When magnesium loses two electrons to form Mg²⁺, it has the electron configuration of 1s² 2s² 2p⁶, which is identical to that of neon. Thus, both Mg²⁺ and Ne have a complete octet in their outer shell.
na is more electropositive. it is so as electropositivity decreases from left to right across a group
If you express your answer as a chemical equation with all forms given, you would get: Mg+(g) + e- -> Mg (g)
A Mg atom has an equal number of protons and electrons, resulting in a neutral charge, while a Mg^2+ ion has lost two electrons, giving it a positive charge. This difference in electron configuration affects the reactivity and chemical properties of each.
An electron configuration with all electron spins paired would indicate a diamagnetic atom. For example, an electron configuration of 1s2 2s2 2p6 3s2 3p6 would be diamagnetic because all the electron spins are paired.
Mg+2 and Br-1
Helium (He) is the element that has a negative electron affinity. This means that it is less likely to gain an electron compared to other elements listed (Kr, O, Ca, and Mg) which have positive electron affinities.
Beryllium (Be) has a greater shielding effect than magnesium (Mg) because it has fewer electron shells. In Be, the single electron in its outer shell experiences less shielding from the inner electrons, while in Mg, the additional electron shells introduce more inner electrons that can shield the outer electrons more effectively. Therefore, the overall shielding effect is greater in Mg due to its larger number of electron shells.
The electron affinity of magnesium (Mg) is lower than that of potassium (K) because Mg is a smaller atom with a fully-filled valence shell, making it less likely to accept an additional electron. In contrast, potassium is a larger atom with an electron configuration that benefits from gaining an electron to achieve a stable inert gas configuration.
The element with the electron configuration 1s22s22p63s23p5 is fluorine (F).
The noble gas that has the same electron configuration as magnesium ion (Mg²⁺) is neon (Ne). When magnesium loses two electrons to form Mg²⁺, it has the electron configuration of 1s² 2s² 2p⁶, which is identical to that of neon. Thus, both Mg²⁺ and Ne have a complete octet in their outer shell.
Magnesium Nitride is Mg3N2. What I think you do is draw it Mg N Mg N Mg and then draw 8 electrons around each Nitrogen so that Mg shares its 2 electrons with Nitrogen and Nitrogen's Pz electron is bumped down into the Px.
Ba has a larger atomic radius than Mg because Ba has more energy levels and electrons than Mg, leading to increased electron-electron repulsion which pushes the outer electrons further apart. This results in a larger atomic radius for Ba compared to Mg.
[Ne]3s2