The energy of a photon can be calculated using the equation (E = \frac{hc}{\lambda}), where (E) is the energy, (h) is Planck's constant ((6.626 \times 10^{-34} , \text{J s})), (c) is the speed of light ((3.00 \times 10^8 , \text{m/s})), and (\lambda) is the wavelength in meters. For a wavelength of 486 nm (which is (486 \times 10^{-9} , \text{m})), the energy comes out to approximately (4.09 \times 10^{-19} , \text{J}) or about (2.55 , \text{eV}).
3.86 x 10-19 J
n nm n n
The peaks of the emission from the ionized vaporof mercury are:-- 184.5 nm . . . UV-C-- 253.7 nm . . . UV-C-- 365.4 nm . . . UV-A-- 404.7 nm . . . violet-- 435.8 nm . . . blue-- 546.1 nm . . . green-- 578.2 nm . . . yellow-orange.The quantum wavelength of the lamp itself is much shorter than any of those.
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
The absorption line at 460 nm corresponds to a transition energy calculated using the formula ( E = \frac{hc}{\lambda} ), where ( h ) is Planck's constant (approximately ( 6.626 \times 10^{-34} ) J·s), ( c ) is the speed of light (about ( 3.00 \times 10^8 ) m/s), and ( \lambda ) is the wavelength in meters. Converting 460 nm to meters gives ( 460 \times 10^{-9} ) m. Plugging in these values, the transition energy is approximately 4.3 eV.
The element that emits a spectral line at 768 nm is hydrogen. The 768 nm spectral line corresponds to the transition of an electron from the 5th energy level to the 2nd energy level in a hydrogen atom.
The cause is the sodium emission line at 589,3 nm.
The transition from energy level 4 to energy level 2 occurs when a hydrogen atom emits light of 486 nm wavelength. This transition represents the movement of an electron from a higher energy level (n=4) to a lower energy level (n=2), releasing energy in the form of light.
Hydrogen, like all elements, have a characteristic distance between energy levels. The atom can only accept photons of energy that match that distance and then that light is emitted. 500 nm does not match the wavelength of light that matches the wavelength corresponding to the energy gap in hydrogen.
The wavelength of the hydrogen atom in the 2nd line of the Balmer series is approximately 486 nm. This corresponds to the transition of an electron from the third energy level to the second energy level in the hydrogen atom.
The hydrogen atom has four spectral lines because it undergoes transitions between its energy levels. These transitions produce four distinct wavelengths of light in the visible spectrum: 656.3 nm, 486.1 nm, 434.0 nm, and 410.2 nm. Each line corresponds to electrons moving between different energy levels in the atom.
3.86 x 10-19 J
3.96 10-19 j
The line spectrum of the hydrogen atom consists of discrete lines at specific wavelengths corresponding to different electron transitions within the atom. These lines are a result of the energy differences between electron orbitals in the atom. Each line represents a specific electron transition, such as the Lyman, Balmer, and Paschen series.
The wavelength of mercury light can vary depending on the specific emission line, but typically falls in the ultraviolet range between 365 to 435 nanometers.
because the emission wavelengths of mercury are very precisely known.
4.32 x 10^-19 j