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The equation for alpha decay from radium-226 (Ra-226) can be represented as follows:

[ \text{Ra-226} \rightarrow \text{Rn-222} + \alpha ]

In this equation, radium-226 (Ra-226) emits an alpha particle (α), which is essentially a helium nucleus, resulting in the formation of radon-222 (Rn-222). This process decreases the atomic number by two and the mass number by four.

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2d ago

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