The equation that represents the dissociation in solution of a salt formed at a trivalent cation and a bivalent anion is typically written as:
M3X2(s) → 3M3+(aq) + 2X2-(aq)
In this equation, M represents the trivalent cation and X represents the bivalent anion. The salt dissociates into three trivalent cations and two bivalent anions in the aqueous solution.
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The equation is: H2O------>H+ + OH-
H2CO3---------- 2 H+ + (CO3)2-
To calculate the acid dissociation constant (Ka) from the original equation, you can use the equilibrium expression that represents the dissociation of the acid and the concentrations of the products and reactants at equilibrium. Ka is equal to the concentration of the products divided by the concentration of the reactants at equilibrium. This value can provide information about the strength of the acid.
The dissociation equation for sulfuric acid (H2SO4) is: H2SO4 - 2H SO42-
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The balanced equation for the dissociation of water is: 2H2O (liquid) ⇌ 2H+ (aqueous) + O2- (aqueous)
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The dissociation equation for CaCl2 in water is: CaCl2 (s) → Ca2+ (aq) + 2Cl- (aq)
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).
The dissociation equation for sodium acetate (NaCH3COO) in water would be: NaCH3COO (s) -> Na+ (aq) + CH3COO- (aq)
The dissociation equation for mercury(II) bromide (HgBr2) in water is: HgBr2(s) -> Hg2+(aq) + 2Br-(aq)
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
The equation is: NaCl----------Na++ Cl-
The reaction is:FeS2 + H2O + 3,5 O2 --------------- FeSO4 + H2SO4It is not a dissociation reaction.
This depends on the reaction; aluminium is trivalent Al(3+).