The equation that represents the dissociation in solution of a salt formed at a trivalent cation and a bivalent anion is typically written as:
M3X2(s) → 3M3+(aq) + 2X2-(aq)
In this equation, M represents the trivalent cation and X represents the bivalent anion. The salt dissociates into three trivalent cations and two bivalent anions in the aqueous solution.
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The equation is: H2O------>H+ + OH-
H2CO3---------- 2 H+ + (CO3)2-
The dissociation equation for aluminum chloride (AlCl₃) in water (H₂O) can be represented as follows: [ \text{AlCl}_3 (s) \rightarrow \text{Al}^{3+} (aq) + 3 \text{Cl}^- (aq) ] This equation shows that one formula unit of AlCl₃ dissociates into one aluminum ion (Al³⁺) and three chloride ions (Cl⁻) when dissolved in water.
The dissociation equation for sulfuric acid (H2SO4) is: H2SO4 - 2H SO42-
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The balanced equation for the dissociation of water is: 2H2O (liquid) ⇌ 2H+ (aqueous) + O2- (aqueous)
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The dissociation equation for CaCl2 in water is: CaCl2 (s) → Ca2+ (aq) + 2Cl- (aq)
The dissociation equation for potassium chromate (K2CrO4) in water is: K2CrO4(s) -> 2K+(aq) + CrO4^2-(aq).
The dissociation equation for sodium acetate (NaCH3COO) in water would be: NaCH3COO (s) -> Na+ (aq) + CH3COO- (aq)
The dissociation equation for mercury(II) bromide (HgBr2) in water is: HgBr2(s) -> Hg2+(aq) + 2Br-(aq)
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
The equation is: NaCl----------Na++ Cl-
The reaction is:FeS2 + H2O + 3,5 O2 --------------- FeSO4 + H2SO4It is not a dissociation reaction.
This depends on the reaction; aluminium is trivalent Al(3+).