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Chlorine gas plus zinc iodide equals?
When chlorine gas reacts with zinc iodide, it forms zinc chloride and iodine. The balanced chemical equation for this reaction is: Cl2 + ZnI2 -> 2 ZnCl2 + I2
What is the Ionic equation for zinc sulfate and tin sulfate?
The ionic equation for the reaction between zinc sulfate (ZnSO₄) and tin sulfate (SnSO₄) is not straightforward because these two compounds do not typically react with each other in a way that produces a net ionic equation. Both are soluble in water and dissociate into their respective ions. However, if you were to write the dissociation, it would be: Zn²⁺(aq) + SO₄²⁻(aq) + Sn²⁺(aq) + SO₄²⁻(aq). Since no reaction occurs, there are no spectator ions to cancel, and thus no net ionic equation can be formed.
What is zinc iodide in roman numerals?
Zinc iodide is a chemical compound composed of zinc and iodine. In Roman numerals, it can be represented as "ZnI₂," where "Zn" stands for zinc and "I" represents iodine. The subscript "2" indicates that there are two iodine atoms for each zinc atom in the compound.
What is the ionic bond Magnesium and Iodine?
Magnesium and iodine react to form the ionic compound magnesium iodide - MgI2.
What is zinc sulfate in chemistry?
Zinc sulfate is an ionic chemical compound.
Is Znl2 an ionic or covalent?
ZnI2 is an ionic compound. It is formed between zinc (Zn), a metal, and iodine (I), a non-metal. Metals typically donate electrons to non-metals to form ionic bonds.
Chlorine gas plus zinc iodide equals?
When chlorine gas reacts with zinc iodide, it forms zinc chloride and iodine. The balanced chemical equation for this reaction is: Cl2 + ZnI2 -> 2 ZnCl2 + I2
What is the net ionic equation for metallic zinc and nitric acid?
Zn + 2H+ ----> Zn2+ + H2
What is the balanced ionic equation for zinc ion and hydrogen gas form when zinc metal reacts with aqueous sulfuric acid?
The balanced ionic equation for the reaction between zinc metal and aqueous sulfuric acid to form zinc ion and hydrogen gas is: Zn(s) + H2SO4(aq) -> Zn^2+(aq) + SO4^2-(aq) + H2(g)
If you combine zinc and iodine what would be the formula of zinc iodide formed?
ZnI2 Zinc has a +2 charge and Iodine has a -1 charge. It takes 2 Iodine to balance on Zinc.
What is the ionic compound for bromine and zinc?
The transition metal zinc (Zn) will form an ionic bond with the halogen bromine (Br) to form the compound zinc bromide (ZnBr2) according to this equation: Zn + 2Br => ZnBr2
What is the net ionic equation of the reaction between zinc and copper 2 sulfate?
The net ionic equation for the reaction between zinc and copper(II) sulfate is: Zn(s) + Cu2+ (aq) -> Zn2+ (aq) + Cu(s). This equation shows the transfer of electrons between zinc and copper ions, resulting in zinc ions in solution and solid copper being formed.
What is ionic charge on iodine?
Iodine typically has an ionic charge of -1.
Is ZnS an ionic compound?
An ionic compound is formed between a metal and a non-metal. Zinc is a metal and iodine is a non-metal. Zinc needs to lose two electrons in order to have a full outer shell, and iodine needs to gain one electron to have a full outer shell. One zinc atom will form a positive ion (Zn2+), and two iodine atoms will gain one electron each from the zinc atom, forming negative ions (I-). As such, the chemical formula of zinc iodide is ZnI2. The equations below demonstrate this.Zn --> Zn2+ + 2e-2I + 2e- --> 2I-
What is the Ionic equation for zinc sulfate and tin sulfate?
The ionic equation for the reaction between zinc sulfate (ZnSO₄) and tin sulfate (SnSO₄) is not straightforward because these two compounds do not typically react with each other in a way that produces a net ionic equation. Both are soluble in water and dissociate into their respective ions. However, if you were to write the dissociation, it would be: Zn²⁺(aq) + SO₄²⁻(aq) + Sn²⁺(aq) + SO₄²⁻(aq). Since no reaction occurs, there are no spectator ions to cancel, and thus no net ionic equation can be formed.
What is the net ionic equation of the reaction of zinc bromide and sodium phosphate combine to produce a precipitate?
The net ionic equation for the reaction between zinc bromide (ZnBr2) and sodium phosphate (Na3PO4) to produce a precipitate of zinc phosphate (Zn3(PO4)2) is: 3Zn^2+ + 2PO4^3- -> Zn3(PO4)2 Since all the ions are participating in the reaction, there is no spectator ion to cancel out in this net ionic equation.
Given that zinc reacts with iodine in the fixed mass ratio of 1 gram of zinc to 3.88 grams of iodine how many grams of iodine are required to completely react with 4.2 grams of zinc?
For every 1 gram of zinc, 3.88 grams of iodine are required to react. So in this case, with 4.2 grams of zinc, the amount of iodine needed would be (4.2 grams zinc) * (3.88 grams iodine / 1 gram zinc) = 16.296 grams of iodine.
