2.38 mol Al
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
45/94.2 is 0.4777 moles
The density of the material is its mass divided by its volume. In this case, the density would be 180 grams / 45 mL = 4 grams/mL.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
To find the number of molecules in 45 grams of aluminum trifluoride (AlF₃), we first need to calculate the molar mass of AlF₃, which is approximately 26.98 g/mol (Al) + 3 × 19.00 g/mol (F) = 83.98 g/mol. Next, we can determine the number of moles in 45 grams by dividing the mass by the molar mass: 45 g / 83.98 g/mol ≈ 0.536 moles. Finally, using Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol), we find the number of molecules: 0.536 moles × (6.022 \times 10^{23}) molecules/mol ≈ (3.22 \times 10^{23}) molecules of AlF₃.
45/94.2 is 0.4777 moles
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
45mL of plain water has a mass of about 45 grams.
45 grams
all i know is that it is 45-50 grams in weight. not mass
45/15= 3 Where density is equal to mass over volume
The density of the material is its mass divided by its volume. In this case, the density would be 180 grams / 45 mL = 4 grams/mL.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
To find the number of moles in 55g of lithium chloride, we first need to calculate the molar mass of lithium chloride, which is approximately 42.39 g/mol. Then, we divide the mass given (55g) by the molar mass to get moles. Therefore, 55g of lithium chloride is approximately 1.30 moles.