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As the Periodic Table of Elements states, Al has a Molar Mass (Grams/Mole) of 27.0g/mol. So 3 mols of Al mass is the same as 3 times 27.0g/mol. So, the equation is as follows: 3mols x 27.0g/mol = 81.0g. The reason on why it ends with grams is because the unit of moles in 3 will cancel out with the unit of mols in 27.0g.
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How many moles of Al(CN)3 are in 235 g of the compound?
To find the number of moles of Al(CN)3 in 235 g, first calculate the molar mass of Al(CN)3. Aluminum (Al) has a molar mass of approximately 26.98 g/mol, and cyanide (CN) has a molar mass of about 26.02 g/mol, so the molar mass of Al(CN)3 is approximately 26.98 + (3 × 26.02) = 105.04 g/mol. Finally, divide the mass of the compound by its molar mass: 235 g ÷ 105.04 g/mol ≈ 2.24 moles of Al(CN)3.
Is there 143g mol in 6.80g of al2o3?
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
How many moles are in 98.3 grams of aluminum hydroxide Al(OH)3?
To find the number of moles in 98.3 grams of aluminum hydroxide (Al(OH)₃), first calculate its molar mass. The molar mass of Al(OH)₃ is approximately 78.00 g/mol (26.98 g/mol for Al + 3 × 16.00 g/mol for O + 3 × 1.01 g/mol for H). Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we have ( \text{moles} = \frac{98.3 , \text{g}}{78.00 , \text{g/mol}} \approx 1.26 , \text{moles} ). So, there are approximately 1.26 moles of aluminum hydroxide in 98.3 grams.
How many grams of Al(OH)3 will be produced when 0.560 mol of CH4 is formed?
To find the number of moles of Al(OH)3 produced, we need to balance the chemical equation for the reaction where CH4 is formed. Once the equation is balanced, we can determine the mole ratio between Al(OH)3 and CH4. If we assume the balanced equation is: 4CH4 + 3O2 -> 2Al(OH)3 + 4H2O, we can see that the mole ratio is 2:4. Therefore, for every 2 moles of Al(OH)3 produced, 4 moles of CH4 are needed. Since we have 0.560 mol of CH4, we will produce half as many moles of Al(OH)3, which is 0.280 mol. To find the mass in grams, we can multiply the moles by the molar mass of Al(OH)3, which is 78 g/mol. Therefore, 0.280 mol of Al(OH)3 will be produced, which is equal to 21.84 grams.
What is the mass in grams for 4.5 moles of aluminum?
2.38 mol Al
How many moles of Al(CN)3 are in 229 g of the compound?
The molar mass of Al(CN)3 is 105.0337 g/mol. To determine the moles Al(CN)3 in 229 g Al(CN)3, multiply the given mass by 1 mol/105.0337 g.229 g Al(CN)3 x 1 mol Al(CN)3/105.0337 g Al(CN)3=2.18 mol Ag(NO)3, rounded to 3 significant figures
How many moles are there in 150 grams of Al(OH)3?
To determine the number of moles in 150 grams of Al(OH)3, we first need to calculate the molar mass of Al(OH)3: Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Molar mass of Al(OH)3 = 26.98 + 3(16.00) + 3(1.01) = 78.03 g/mol Now, we can calculate the number of moles: Number of moles = Mass (g) / Molar mass Number of moles = 150 g / 78.03 g/mol ≈ 1.92 moles.
What percentage composition of Al2O3 is aluminum?
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
How many moles of Al(CN)3 are in 163 grams of the compound?
To find the number of moles of Al(CN)3 in 163 grams, you need to first calculate the molar mass of Al(CN)3. The molar mass of Al = 26.98 g/mol, C = 12.01 g/mol, N = 14.01 g/mol. Add these together with the appropriate subscripts for the compound to get the molar mass of Al(CN)3. Then, divide the given mass (163 g) by the molar mass to find the number of moles.
Molar mass of AlOH3?
The molar mass of AlOH3 is calculated by adding the atomic masses of each element in its chemical formula. Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Therefore, the molar mass of AlOH3 is 78.02 g/mol.
What is the formula mass for aluminium hydroxide?
The formula mass of aluminium hydroxide (Al(OH)3) can be calculated by adding the atomic mass of each element in the compound. The atomic mass of aluminium (Al) is 26.98 g/mol, oxygen (O) is 16.00 g/mol, and hydrogen (H) is 1.01 g/mol. Therefore, the formula mass of aluminium hydroxide is approximately 78.0 g/mol.
What is the mass in grams of 1.00 mol Al?
7 X 102 g Al this is the awnser using significant figures
Is there 143g mol in 6.80g of al2o3?
To determine if there are 143 g/mol in 6.80 g of Al₂O₃, we first need to calculate the molar mass of Al₂O₃. The molar mass of Al₂O₃ is approximately 102 g/mol (with aluminum at about 27 g/mol and oxygen at about 16 g/mol). To find the number of moles in 6.80 g of Al₂O₃, we divide the mass by the molar mass: 6.80 g ÷ 102 g/mol ≈ 0.067 moles. Thus, there are no 143 g/mol in 6.80 g of Al₂O₃; the molar mass is actually around 102 g/mol.
What is the molar mass of HNO3?
The molar mass of Ag NO3 is 169.8731 g/mol
What is the mass for Aluminum Chlorate formula?
The molar mass of aluminum chlorate (Al(ClO3)3) is approximately 277.34 g/mol.
What is the molar mass of aluminum acetate?
The molar mass of aluminum acetate (Al(C2H3O2)3) is approximately 204.11 g/mol.
How many moles are in 98.3 grams of aluminum hydroxide Al(OH)3?
To find the number of moles in 98.3 grams of aluminum hydroxide (Al(OH)₃), first calculate its molar mass. The molar mass of Al(OH)₃ is approximately 78.00 g/mol (26.98 g/mol for Al + 3 × 16.00 g/mol for O + 3 × 1.01 g/mol for H). Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we have ( \text{moles} = \frac{98.3 , \text{g}}{78.00 , \text{g/mol}} \approx 1.26 , \text{moles} ). So, there are approximately 1.26 moles of aluminum hydroxide in 98.3 grams.
