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What is the empirical formula of a compound that contains 75 percent Ag and 25 percent Cl by mass?
The empirical formula of the compound would be AgCl, as the ratio of silver to chlorine in the compound is 3:1 based on the given mass percentages (75% Ag and 25% Cl). This ratio simplifies to AgCl when expressed in the simplest whole number ratio.
What is the atomic mass unit of cl?
The atomic mass unit of chlorine (Cl) is approximately 35.45.
Cl-35 75.8 percent and cl-37 24.3 percent what is atomic mass?
The atomic mass of chlorine can be calculated using the percentages given for Cl-35 and Cl-37. Multiply the mass of each isotope by its percentage, then add the results together to find the average atomic mass. For Cl-35 (mass 35) with 75.8% abundance and Cl-37 (mass 37) with 24.3% abundance, the atomic mass = (35 x 0.758) + (37 x 0.243) = 35.5.
What is the emperical formula of a sample that has 80g Ca and 140g Cl?
The molar mass of Ca is 40 g/mol, and the molar mass of Cl is 35.5 g/mol. To find the empirical formula, we must first convert the masses to moles. 80 g Ca is 2 moles and 140 g Cl is 4 moles. To get the simplest whole number ratio, we divide by the smallest number of moles, giving us a ratio of 1 Ca to 2 Cl atoms, and the empirical formula is CaCl2.
Is the mass of an atom of chlorine-37 greater or less than an atom of chlorine -35?
The mass of Cl-37 is greater than that of Cl-35. Because Cl-37 has two neutrons more than Cl-35.
What is the mass of 0.500 mol of dichlorodifluoromethane CCl2F2?
To find the mass of 0.500 mol of dichlorodifluoromethane (CCl2F2), you need to calculate the molar mass of the compound. The molar mass of CCl2F2 is 120.91 g/mol. Therefore, 0.500 mol of CCl2F2 would have a mass of 0.500 mol x 120.91 g/mol = 60.455 g.
What is the mass ratio of Na to Cl in sodium chloride?
The ratio mass of chlorine/mass of sodium is 1,5.
What is one mole of freon CCl2F2 the chemical ratio of carbon to chloride to fluorine is 2-1-2?
One mole of freon CCl2F2 contains 1 atom of carbon, 2 atoms of chloride, and 2 atoms of fluorine. The chemical ratio of carbon to chloride to fluorine in freon CCl2F2 is 1:2:2.
What elements make up CCL2f2?
One atom of Carbon, two atoms of Chlorine, and two atoms of Fluorine.
Is the chemical ratio of carbon to chlorine to fluorine 2 to 1 to 2 in CCI2F2?
No, the chemical ratio of carbon to chlorine to fluorine in CCl2F2 is 1:2:2, meaning there is 1 carbon atom, 2 chlorine atoms, and 2 fluorine atoms in each molecule of CCl2F2.
What is one mole of freon CCl2F2 the chemical ratio of carbon to chloride to fluorine is 2 1 2?
False
What is the empirical formula of a compound that contains 75 percent Ag and 25 percent Cl by mass?
The empirical formula of the compound would be AgCl, as the ratio of silver to chlorine in the compound is 3:1 based on the given mass percentages (75% Ag and 25% Cl). This ratio simplifies to AgCl when expressed in the simplest whole number ratio.
How many atoms in ccl2f2?
There are a total of 9 atoms in CCl2F2: 1 carbon atom, 2 chlorine atoms, and 2 fluorine atoms.
What is the atomic mass unit of cl?
The atomic mass unit of chlorine (Cl) is approximately 35.45.
If you wanted to combine equal numbers of Na and Cl in a flask how much Cl would you have to add if you added twenty three g of Na?
You would need to add 35.5 g of Cl to combine with 23 g of Na. This is because Na and Cl combine in a 1:1 ratio by mass based on their atomic weights (Na = 23 g/mol, Cl = 35.5 g/mol).
Cl-35 75.8 percent and cl-37 24.3 percent what is atomic mass?
The atomic mass of chlorine can be calculated using the percentages given for Cl-35 and Cl-37. Multiply the mass of each isotope by its percentage, then add the results together to find the average atomic mass. For Cl-35 (mass 35) with 75.8% abundance and Cl-37 (mass 37) with 24.3% abundance, the atomic mass = (35 x 0.758) + (37 x 0.243) = 35.5.
What is the emperical formula of a sample that has 80g Ca and 140g Cl?
The molar mass of Ca is 40 g/mol, and the molar mass of Cl is 35.5 g/mol. To find the empirical formula, we must first convert the masses to moles. 80 g Ca is 2 moles and 140 g Cl is 4 moles. To get the simplest whole number ratio, we divide by the smallest number of moles, giving us a ratio of 1 Ca to 2 Cl atoms, and the empirical formula is CaCl2.
