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To calculate the molality (m) of a solution, you need to know the number of moles of solute and the mass of the solvent in kilograms. If you dissolve 2 moles of solute in a specific mass of solvent, you can use the formula: ( m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} ). Without the mass of the solvent, the molality cannot be determined. Please provide the mass of the solvent for a complete answer.
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What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg?
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
What is the molality of a solution made by dissolving 2 miles of NaOH in 6 kg of water?
To calculate the molality of a solution, use the formula: molality (m) = moles of solute / mass of solvent in kilograms. Here, you have 2 moles of NaOH and 6 kg of water. Therefore, the molality is 2 moles / 6 kg = 0.33 mol/kg. Thus, the molality of the NaOH solution is 0.33 m.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a substance made by dissolving 2 moles of NaOH in 10 kg of water?
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water Apex?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 2 moles of NaOH dissolved in 6 kg of water, the molality is ( m = \frac{2 , \text{moles}}{6 , \text{kg}} = \frac{1}{3} , \text{mol/kg} ). Therefore, the molality of the solution is approximately 0.33 mol/kg.
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg?
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
What is the molality of a solution made by a dissolving 2 moles of naoh in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a solution made by dissolving two moles of NaOH in 6 kg of water?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
What is the molality of a solution made by dissolving 2 miles of NaOH in 6 kg of water?
To calculate the molality of a solution, use the formula: molality (m) = moles of solute / mass of solvent in kilograms. Here, you have 2 moles of NaOH and 6 kg of water. Therefore, the molality is 2 moles / 6 kg = 0.33 mol/kg. Thus, the molality of the NaOH solution is 0.33 m.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the molality of a solution made by dissolving 2 moles of NaOH in 6 kg of water?
0.33 mol/kg (apex)
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?
0.2
What is the molality of a solution made by dissolving 2 moles of NaOH in 6kg of water?
0.33 mol/kg
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
