To calculate the molality (m) of a solution, you need to know the number of moles of solute and the mass of the solvent in kilograms. If you dissolve 2 moles of solute in a specific mass of solvent, you can use the formula: ( m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} ). Without the mass of the solvent, the molality cannot be determined. Please provide the mass of the solvent for a complete answer.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 2 moles of NaOH dissolved in 6 kg of water, the molality is ( m = \frac{2 , \text{moles}}{6 , \text{kg}} = \frac{1}{3} , \text{mol/kg} ). Therefore, the molality of the solution is approximately 0.33 mol/kg.
2 mol/kg
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
Molality (m) is defined as moles of solute per kg of solvent.Thus, 2 moles/6 kg = 0.33 molal or 0.3 m.
0.33 mol/kg (apex)
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
Molality =moles of solute/kilograms of solvent Moles of solute =2
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
0.33 mol/kg (apex)
0.2
0.33 mol/kg
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.