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Molality is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms. In this case, the solution has 3 moles of glucose dissolved in 6 kg of water. Therefore, the molality (m) is 3 mol / 6 kg = 0.5 mol/kg. Thus, the molality of the solution is 0.5 m.
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What is the morality solution that has 3 mol of glucose in 6 kg if water?
To calculate the molality (m) of a solution, you use the formula: ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, with 3 moles of glucose in 6 kg of water, the molality would be ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 6 mol of CACI2 on 3 kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). For a solution with 6 moles of CaCl₂ dissolved in 3 kg of water, the molality would be ( m = \frac{6 \text{ mol}}{3 \text{ kg}} = 2 \text{ mol/kg} ). Therefore, the molality of the solution is 2 mol/kg.
What is the boiling point of a solution of 0.10 mole of glucose in 200ml of water?
To determine the boiling point of a solution of glucose in water, we first calculate the molality of the solution. With 0.10 moles of glucose in 200 mL of water (approximately 0.2 kg), the molality is 0.5 mol/kg. The boiling point elevation can be calculated using the formula ΔT_b = i * K_b * m, where K_b for water is 0.512 °C kg/mol. Thus, the boiling point elevation is approximately 0.26 °C, raising the boiling point of water from 100 °C to about 100.26 °C.
What is the molality of a solution that has 6 mol of cac2 in 3 kg of water?
To calculate the molality (m) of a solution, use the formula: [ m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} ] In this case, there are 6 moles of calcium carbide (CaC₂) and 3 kg of water. Thus, the molality is: [ m = \frac{6 , \text{mol}}{3 , \text{kg}} = 2 , \text{mol/kg} ] Therefore, the molality of the solution is 2 mol/kg.
What is the molality of solution made by combining 5.0 g of CaCI2 with 500.0g of water?
To calculate the molality of the solution, first determine the number of moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so 5.0 g of CaCl₂ corresponds to about 0.045 moles (5.0 g / 110.98 g/mol). Molality (m) is defined as moles of solute per kilogram of solvent; with 500.0 g of water (0.500 kg), the molality is ( m = \frac{0.045 \text{ moles}}{0.500 \text{ kg}} = 0.090 , \text{mol/kg} ). Thus, the molality of the solution is 0.090 mol/kg.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
What is the molality of a solution of 90 grams of glucose C6H12OSUB6 dissolved in 800 grams of water?
first determine the number ofmoles dissolved in given solution then .5 moles moles dissolved in 800g. as comparison with 1000g of water, we know 100g of water dissolve only.1 moles of a glucose so we .7moles of glucose dissolve in 800g.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the molality of a solution the has 3 mol of glucose on 6 kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 0.5 mol/kg since there are 3 moles of glucose in 6 kg of water.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg water?
Molality = moles of solute / kilograms of solventm = 5.10 / 4.47m = 1.14 molal
