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What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the gram fromula mass of CaCl2?
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
What is the gram formula mass of CaCl2?
The gram formula mass of CaCl2 is approximately 110.98 g/mol. This is calculated by adding the atomic masses of the elements in the compound, which are 40.08 g/mol for calcium (Ca) and 35.45 g/mol for each chlorine (Cl) atom.
What is the number of molecules equal to 1.46 moles of CaCl2?
To find the number of molecules in 1.46 moles of CaCl2, you would first calculate the molar mass of CaCl2 (110.98 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. This would give you approximately 8.80 x 10^23 molecules of CaCl2.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
How many moles of ions are in the solutionCalcium chloride (CaCl2) is an ionic compound that dissociates in water. A chemist forms a solution by mixing 0.50 mol CaCl2 and 1.0 kg of water?
When CaCl2 dissociates in water, it forms three ions: one Ca2+ ion and two Cl- ions for each formula unit of CaCl2. Therefore, 0.50 mol of CaCl2 would yield 0.50 mol Ca2+ ions and 1.0 mol Cl- ions in solution, totaling 1.5 moles of ions.
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
If 3.0 mol of CaCl2 are added to water to make 0.500L of solution what is the concentration in molarity?
molarity is #moles divide by # liters, so 3.0 divided by 0.500 is 6.0 molarity (2 siginficant figures is all you are allowed)
What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?
First, calculate the molar mass of CaCl2, which is 110.98 g/mol. Next, calculate the number of moles of CaCl2 in 330 grams using the formula moles = mass / molar mass. This gives you 2.97 mol of CaCl2. Finally, divide the moles of CaCl2 by the volume of the solution in liters to get the molarity, which is 2.97 M.
How many moles of solute are contained in the following solution 17.33 mL 2.17 M CaCl2?
To find the moles of solute, first calculate the amount of CaCl2 in the solution: 17.33 mL * 2.17 mol/L = 37.6561 mmol of CaCl2. Then convert this to moles: 37.6561 mmol / 1000 = 0.0377 mol of CaCl2 in the solution.
How would you make 1 liter of a 1 molar solution of CaCl2?
To make 1 liter of a 1 molar solution of CaCl2, you would need to dissolve 147.02 grams of CaCl2 in enough water to make a final volume of 1 liter. This formula weight comes from the atomic weights of calcium (40.08 g/mol) and chlorine (35.45 g/mol).
What is the mass of 0.89 mol of CaCl2?
To find the mass of 0.89 mol of CaCl2, you need to multiply the molar mass of CaCl2 by 0.89 mol. The molar mass of CaCl2 is 110.98 g/mol. Therefore, the mass of 0.89 mol of CaCl2 would be 98.882 g.
How many grams of CaCl2 are needed to prepare 2.00 l if 0.700 M CaCl2 solution?
The gram formula mass of CaCl2 is 110.99. By definition, each liter of 0.700 M CaCl2 contains 0.700 gram formula masses of the solute. Therefore, 2.00 liters of such solution contain 1.400 formula masses of the solute, or 155 grams, to the justified number of significant digits.
