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Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). For a solution with 6 moles of CaCl₂ dissolved in 3 kg of water, the molality would be ( m = \frac{6 \text{ mol}}{3 \text{ kg}} = 2 \text{ mol/kg} ). Therefore, the molality of the solution is 2 mol/kg.
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What is the molality of a solution that has 6 mol of CaCI2 in 3kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 6 moles of CaCl₂ dissolved in 3 kg of water, the molality would be ( m = \frac{6 , \text{mol}}{3 , \text{kg}} = 2 , \text{mol/kg} ). Therefore, the molality of the solution is 2 mol/kg.
What is the molality of solution made by combining 5.0 g of CaCI2 with 500.0g of water?
To calculate the molality of the solution, first determine the number of moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so 5.0 g of CaCl₂ corresponds to about 0.045 moles (5.0 g / 110.98 g/mol). Molality (m) is defined as moles of solute per kilogram of solvent; with 500.0 g of water (0.500 kg), the molality is ( m = \frac{0.045 \text{ moles}}{0.500 \text{ kg}} = 0.090 , \text{mol/kg} ). Thus, the molality of the solution is 0.090 mol/kg.
What is the molality of a solution that as 3 mol of glucose in 6 kg of water?
Molality is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms. In this case, the solution has 3 moles of glucose dissolved in 6 kg of water. Therefore, the molality (m) is 3 mol / 6 kg = 0.5 mol/kg. Thus, the molality of the solution is 0.5 m.
What is the molality of a solution that has 3 mol of glucose in 6kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, there are 3 moles of glucose and 6 kg of water. Therefore, the molality of the solution is ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Thus, the molality of the solution is 0.5 mol/kg.
What is the molatiy of a solution that has 6 mol of CaCl2 in 3 kg of water?
To find the molality of the solution, you can use the formula: molality (m) = moles of solute / mass of solvent (in kg). In this case, there are 6 moles of CaCl2 and 3 kg of water. Therefore, the molality is 6 mol / 3 kg = 2 m. Thus, the molality of the solution is 2 molal.
What is the molality of a solution that has 6 mol of CaCI2 in 3kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). In this case, with 6 moles of CaCl₂ dissolved in 3 kg of water, the molality would be ( m = \frac{6 , \text{mol}}{3 , \text{kg}} = 2 , \text{mol/kg} ). Therefore, the molality of the solution is 2 mol/kg.
What is the molality of solution made by combining 5.0 g of CaCI2 with 500.0g of water?
To calculate the molality of the solution, first determine the number of moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so 5.0 g of CaCl₂ corresponds to about 0.045 moles (5.0 g / 110.98 g/mol). Molality (m) is defined as moles of solute per kilogram of solvent; with 500.0 g of water (0.500 kg), the molality is ( m = \frac{0.045 \text{ moles}}{0.500 \text{ kg}} = 0.090 , \text{mol/kg} ). Thus, the molality of the solution is 0.090 mol/kg.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molality of a solution that as 3 mol of glucose in 6 kg of water?
Molality is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms. In this case, the solution has 3 moles of glucose dissolved in 6 kg of water. Therefore, the molality (m) is 3 mol / 6 kg = 0.5 mol/kg. Thus, the molality of the solution is 0.5 m.
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
What is the molality of a solution that has 3 mol of glucose in 6kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, there are 3 moles of glucose and 6 kg of water. Therefore, the molality of the solution is ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Thus, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
