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What is the morality solution that has 3 mol of glucose in 6 kg if water?
To calculate the molality (m) of a solution, you use the formula: ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, with 3 moles of glucose in 6 kg of water, the molality would be ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution that has 6mol of CaCl2 in 3 kg of water?
Molality = moles solute per kg solventmoles solute = 6 moles CaCl2kg solvent = 3 kg watermolality = 6 mole/3 kg = 2 m
What is the molality of a solution that has 6 mol of cac2 in 3 kg of water?
To calculate the molality (m) of a solution, use the formula: [ m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} ] In this case, there are 6 moles of calcium carbide (CaC₂) and 3 kg of water. Thus, the molality is: [ m = \frac{6 , \text{mol}}{3 , \text{kg}} = 2 , \text{mol/kg} ] Therefore, the molality of the solution is 2 mol/kg.
What is the molality of a solution by dissolving 2 moles of NaOH in 10kg of water?
10kg of water contains 10l of water. So morality is 0.2mildm-3.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution the has 3 mol of glucose on 6 kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 0.5 mol/kg since there are 3 moles of glucose in 6 kg of water.
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is the molality of a solution that has 6mol of CaCl2 in 3 kg of water?
Molality = moles solute per kg solventmoles solute = 6 moles CaCl2kg solvent = 3 kg watermolality = 6 mole/3 kg = 2 m
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molality of a solution that has 70g of NaCl dissolved in 300g of water?
Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00
The density of 3 M solution of NaCl is 1.25 g mL-1 Calculate the molality of the solution?
To calculate the molality of the solution, you first need to find the molar mass of NaCl, which is 58.44 g/mol. Next, calculate the mass of NaCl in 1 L of the solution by multiplying the density (1.25 g/mL) by 1000 mL. Then divide the mass of NaCl by the molar mass to find the number of moles. Finally, divide the moles by the mass of the solvent (in kg) to get the molality. In this case, the molality is approximately 1.30 mol/kg.
