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To calculate the molality of a solution, you need to know the mass of the solvent (in kilograms) in which the solute is dissolved. Molality (m) is defined as the number of moles of solute per kilogram of solvent. If you only have the number of moles of glucose (3 moles), you cannot determine the molality without the mass of the solvent. Please provide the mass of the solvent for a complete calculation.
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What is the molality of a solution that as 3 mol of glucose in 6 kg of water?
Molality is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms. In this case, the solution has 3 moles of glucose dissolved in 6 kg of water. Therefore, the molality (m) is 3 mol / 6 kg = 0.5 mol/kg. Thus, the molality of the solution is 0.5 m.
What is the molality of a solution that has 3 mol of glucose in 6kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, there are 3 moles of glucose and 6 kg of water. Therefore, the molality of the solution is ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Thus, the molality of the solution is 0.5 mol/kg.
What is the morality solution that has 3 mol of glucose in 6 kg if water?
To calculate the molality (m) of a solution, you use the formula: ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, with 3 moles of glucose in 6 kg of water, the molality would be ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Therefore, the molality of the solution is 0.5 mol/kg.
What is the molatiy of a solution that has 6 mol of CaCl2 in 3 kg of water?
To find the molality of the solution, you can use the formula: molality (m) = moles of solute / mass of solvent (in kg). In this case, there are 6 moles of CaCl2 and 3 kg of water. Therefore, the molality is 6 mol / 3 kg = 2 m. Thus, the molality of the solution is 2 molal.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution that as 3 mol of glucose in 6 kg of water?
Molality is calculated by dividing the number of moles of solute by the mass of the solvent in kilograms. In this case, the solution has 3 moles of glucose dissolved in 6 kg of water. Therefore, the molality (m) is 3 mol / 6 kg = 0.5 mol/kg. Thus, the molality of the solution is 0.5 m.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution the has 3 mol of glucose on 6 kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality would be 0.5 mol/kg since there are 3 moles of glucose in 6 kg of water.
What is the molality of a solution that has 3 mol of glucose in 6kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, there are 3 moles of glucose and 6 kg of water. Therefore, the molality of the solution is ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Thus, the molality of the solution is 0.5 mol/kg.
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the morality solution that has 3 mol of glucose in 6 kg if water?
To calculate the molality (m) of a solution, you use the formula: ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, with 3 moles of glucose in 6 kg of water, the molality would be ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Therefore, the molality of the solution is 0.5 mol/kg.
What is the molatiy of a solution that has 6 mol of CaCl2 in 3 kg of water?
To find the molality of the solution, you can use the formula: molality (m) = moles of solute / mass of solvent (in kg). In this case, there are 6 moles of CaCl2 and 3 kg of water. Therefore, the molality is 6 mol / 3 kg = 2 m. Thus, the molality of the solution is 2 molal.
What is the molality of a solution made by dissolving 3 mol of NaOH in 6 kg of water?
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
What is the molality of a solution made by dissolving 2 moles of NaOH in 10Kg of water?
Molality =moles of solute/kilograms of solvent Moles of solute =2
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is the molality of a solution that has 6mol of CaCl2 in 3 kg of water?
Molality = moles solute per kg solventmoles solute = 6 moles CaCl2kg solvent = 3 kg watermolality = 6 mole/3 kg = 2 m
