Molality = moles solute per kg solvent
moles solute = 6 moles CaCl2
kg solvent = 3 kg water
molality = 6 mole/3 kg = 2 m
6mol/2L
6mol
First you need a balanced equation: Al2O3 + 6HCl -> 2AlCl3 + 3H2O then you do a simple mole conversion: 1mol HCL/1 X 1mol Al2O3/ 6mol HCl which is (1 X 1) / (1 X 6) = 1/6mol Al2O3 is needed.
One drop of 0.1M NaOH solution contains about 0.1(mol/L) * 0.05(mL) * 10-3(L/mL) = 5*10-6 mol OH-.When this is added to 1 L of 0.1M HCl the remaining [H+] will be changed from 0.1M = 100,000*10-6mol to 99,995*10-6 mol H+ ( pH= 1.00002 in stead of 1.0). This is far beyond measure accuracy limits.However when added at neutralisation point, where at pH = 7 only H+ from water is present with also: 1.0*10-7mol OH-/L and this will change to (about) 5.1*10-6 mol OH- , so pH = 14.0 - [-log( 5.1*10-6)] = 14.0-5.3 = 8.7 (the [OH-] has increased 51 fold)
Divide 96 by molecular mass.So the answer is 6mol
To find the grams of sodium formed, we need to first determine the molar mass of Na3N, which is 84 g/mol. From the balanced equation, we see that for every 2 moles of Na3N that decompose, 6 moles of sodium are formed. Therefore, using the molar mass of Na (23 g/mol), we can calculate that 100.0 grams of Na3N would produce 85.71 grams of sodium.
1) single replacement reaction: Cl2 (g) + 2KI (s) --> 2KCl (s) + I2 (g) 2) correctly balanced equation: 4Al (s) + 3O2 (g) --> 2Al2O3 (s) 3) liters of hydrogen gas are required to produce 2 moles of NH3 2mol NH3 = 44.8 litres at STP 3litres N2 produce 2 litres NH3 vol H2 = 44.8*3/2 = 67.2 litres N2 required 4)grams of oxygen are required to produce 1 mole of H2O? 3mol O2 produce 6mol H2O 0.5mol O2 will produce 1 mol H2O Molar mass O2 = 32g/mol 0.5mol = 16g O2
V1= x says V2 = 1000-x M1=10mol/L M2=3mol/L M = 6mol/L M = (M1V1+M2V2)/(V1+V2) 6={10*x+3(1000-x)}/(x+1000-x) 6000=7x+3000 x=428.57 V1= 428.57ml V2= 1000-428.57 V2= 571.2ml so, the volume of 10M HCl =428.57ml the volume of 3M HCl =571.2ml IT IS DONE BY JAGADEESH SAI VINOD
Divide 96 by molecular mass.So the answer is 6mol
glucose 1 mole has 180,156 grams and has 6.022 x 1023 atoms carbon 1 mole has 12,01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72,06 grams out of the 180,156. Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram of glucose.