First you need a balanced equation: Al2O3 + 6HCl -> 2AlCl3 + 3H2O
then you do a simple mole conversion: 1mol HCL/1 X 1mol Al2O3/ 6mol HCl which is (1 X 1) / (1 X 6) = 1/6mol Al2O3 is needed.
There are three oxygen atoms present in a formula unit of Aluminum Hydroxide (Al(OH)3).
Sodium hydroxide does not react with platinum under normal conditions as platinum is inert to many chemical reagents, including sodium hydroxide. Platinum is often used in chemical processes precisely because of its resistance to corrosion and reactivity.
To convert from molecules to moles, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Therefore, 98.3 molecules of aluminum hydroxide would be approximately 0.163 moles.
To determine the grams of aluminum hydroxide produced from 14.2g of aluminum sulfide, first calculate the molar mass of aluminum sulfide by adding the atomic masses of aluminum and sulfur. Then, use the stoichiometry of the balanced chemical equation to find the molar ratio between aluminum sulfide and aluminum hydroxide. Next, convert the 14.2g of aluminum sulfide to moles, and then use the molar ratio to find the moles of aluminum hydroxide produced. Finally, convert the moles of aluminum hydroxide to grams using its molar mass.
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
Magnesium hydroxide/aluminum hydroxide. This is basically Maalox.
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
There are three oxygen atoms present in a formula unit of Aluminum Hydroxide (Al(OH)3).
Al(OH)3 One atom of aluminum. Three atoms of oxygen. Three atoms of hydrogen.
Three hydroxide ions are needed to form a neutral ionic compound with an aluminum ion. Aluminum has a charge of +3, while hydroxide has a charge of -1 per ion. Therefore, the formula Al(OH)3 is needed for a neutral compound.
Sodium hydroxide does not react with platinum under normal conditions as platinum is inert to many chemical reagents, including sodium hydroxide. Platinum is often used in chemical processes precisely because of its resistance to corrosion and reactivity.
155.2 g
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
Aluminium Hydroxide contains elements of Aluimium, Hydrogen and Oxygen.
To convert from molecules to moles, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Therefore, 98.3 molecules of aluminum hydroxide would be approximately 0.163 moles.