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To calculate the molality (m) of a solution, use the formula:
[ m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}} ]
In this case, there are 6 moles of calcium carbide (CaC₂) and 3 kg of water. Thus, the molality is:
[ m = \frac{6 , \text{mol}}{3 , \text{kg}} = 2 , \text{mol/kg} ]
Therefore, the molality of the solution is 2 mol/kg.
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What is the molality of a solution that has 6 mol of CACI2 on 3 kg of water?
Molality (m) is calculated using the formula ( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} ). For a solution with 6 moles of CaCl₂ dissolved in 3 kg of water, the molality would be ( m = \frac{6 \text{ mol}}{3 \text{ kg}} = 2 \text{ mol/kg} ). Therefore, the molality of the solution is 2 mol/kg.
What is the morality solution that has 3 mol of glucose in 6 kg if water?
To calculate the molality (m) of a solution, you use the formula: ( m = \frac{\text{moles of solute}}{\text{kg of solvent}} ). In this case, with 3 moles of glucose in 6 kg of water, the molality would be ( m = \frac{3 , \text{mol}}{6 , \text{kg}} = 0.5 , \text{mol/kg} ). Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of solution made by combining 5.0 g of CaCI2 with 500.0g of water?
To calculate the molality of the solution, first determine the number of moles of CaCl₂. The molar mass of CaCl₂ is approximately 110.98 g/mol, so 5.0 g of CaCl₂ corresponds to about 0.045 moles (5.0 g / 110.98 g/mol). Molality (m) is defined as moles of solute per kilogram of solvent; with 500.0 g of water (0.500 kg), the molality is ( m = \frac{0.045 \text{ moles}}{0.500 \text{ kg}} = 0.090 , \text{mol/kg} ). Thus, the molality of the solution is 0.090 mol/kg.
What is the molality of a solution that contains 2 moles of glycerin and dissolved in 1000 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, there are 2 moles of glycerin dissolved in 1000 g of water, which is equivalent to 1 kg. Therefore, the molality is 2 mol / 1 kg = 2 mol/kg.
How do you calculate the molality of 10g of NaCI in 2kg of water?
To calculate the molality (m) of a solution, use the formula: [ \text{molality} (m) = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}. ] First, convert the mass of NaCl into moles by using its molar mass (approximately 58.44 g/mol). For 10 g of NaCl, you have: [ \text{moles of NaCl} = \frac{10 , \text{g}}{58.44 , \text{g/mol}} \approx 0.171 , \text{mol}. ] Then, divide the moles by the mass of the solvent (water) in kilograms: [ m = \frac{0.171 , \text{mol}}{2 , \text{kg}} \approx 0.0855 , \text{mol/kg}. ] So, the molality of the solution is approximately 0.0855 mol/kg.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the molality of solution that has 3 mol of glucose in 6 Kg of water?
3mol/6kg
What is the molality of a solution that has 3 mol of glucose in 6 kg of water?
The molality of the solution is 0.5 mol/kg. This is calculated by dividing the number of moles of solute (3 mol glucose) by the mass of solvent in kilograms (6 kg water).
What is the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg water?
Molality = moles of solute / kilograms of solventm = 5.10 / 4.47m = 1.14 molal
What is the molality of a solution made by dissolving 2 mole of NaOH in 6kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 2 moles of NaOH dissolved in 6 kg of water. Therefore, the molality would be 2 mol / 6 kg = 0.33 mol/kg.
What would you need to do to calculate the molality of 10 mol of NaCl in 200 mol of water?
Convert the 200 mol of water to kilograms of water.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
