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What is molar mass for ammonium peroxide?

(NH4)2O2 molar mass = 2*14+2*4+2*16 = 28+8+32 = 36+32 = 110 according to physics : weight = mass * gravity so, molar mass = 110/10 = 11


What is the molar mass ammonium phosphate(NH4)3PO4?

14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.


What is the percent composition of nitrogen in NH42HPO4?

To calculate the percent composition of nitrogen in NH4 2HPO4, first calculate the molar mass of NH4 2HPO4 ( nitrogen: 14.01 g/mol, hydrogen: 1.01 g/mol, phosphorus: 30.97 g/mol, oxygen: 16.00 g/mol). Then, find the molar mass of nitrogen in NH4 2HPO4 ( nitrogen: 14.01 g/mol x 2). Finally, divide the molar mass of nitrogen by the molar mass of NH4 2HPO4 and multiply by 100 to get the percent composition of nitrogen.


How many moles of (NH4)2S are there in 150 g of (NH4)2S?

To find the number of moles in 150 g of (NH4)2S, we first need to calculate the molar mass of (NH4)2S. The molar mass of (NH4)2S is 68.15 g/mol. Next, we use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 150 g / 68.15 g/mol, which is approximately 2.20 moles of (NH4)2S.


What is the mass percent of nitrogen in ammonia carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate ((NH4)2CO3), first find the molar mass of the compound: (2 x 14) + 12 + 3 x 16 = 96 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. The mass percent of nitrogen in (NH4)2CO3 is (2 x 14) / 96 x 100 = 29.2%.


What is the percentage by mass of nitrogen in ammonium sulphate?

Ammonium sulfate has the chemical formula (NH4)2SO4. The molar mass of nitrogen is 14.01 g/mol and the molar mass of (NH4)2SO4 is 132.14 g/mol. Therefore, the percentage by mass of nitrogen in ammonium sulfate is (2*14.01)/(132.14) * 100% = 21.2%.


What is the mass percent of nitrogen in ammonium carbonate (NH4)2CO3?

To calculate the mass percent of nitrogen in ammonium carbonate (NH4)2CO3, first find the molar mass of the compound: 2(N) + 8(H) + 1(C) + 3(O) = 96 g/mol. The molar mass of nitrogen in the compound is 2(N) = 28 g/mol. To find the mass percent of nitrogen, divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100: (28 g/mol / 96 g/mol) x 100 = 29.2%.


How many moles of ammonium ions are in 8.790g of ammonium carbonate?

Ammonium carbonate is (NH4 )2 CO3 and the molar mass is 96.0878 so you just divide 8.790 g/96.0878 and you get 0.91478835 and since there are two ammonium (NH4 )2 ions you multiply 0.91478835 * 2 and get 0.1830 mol.


What is the percent and the weight of nitrogen in 8.941 mol of ammonium sulfide?

Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.


Determine both the formula mass and molar mass of ammonium carbonate?

The formula mass of ammonium carbonate (NH4)2CO3 is 96.09 g/mol. Since the formula contains two ammonium ions, the molar mass of ammonium carbonate is 96.09 g/mol * 2 = 192.18 g/mol.


How many moles of ammonium ions are in 6.965 of ammonium carbonate?

To find the number of moles of ammonium ions, we first calculate the molar mass of ammonium carbonate (NH4)2CO3. It is 96.086 g/mol. Then we can find the moles of (NH4)2 cations in 6.965 g by dividing the mass by the molar mass. This gives us 0.0726 moles of ammonium ions.


What is the molar mass of lead(III) phosphate Pb3(PO4)2.?

The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.