c12h24
Molar Mass
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
graham's law (Rate 1 / rate 2) ^2 = MM2 / MM1 (Rate x / rate Ar) ^2 = MM Ar / MM x (.907)^2 = 39.9481 / MMx MMx = 39.9481 / 0.8226 Molar mass of unknown gas = 48.56 g / mole
c12h24
c12h24
The molecular formula of the compound is C2H4, which has a molar mass of 28 g/mol. Since the given compound has a molar mass of 42.0 g/mol, it must include an additional CH2 group, resulting in the molecular formula C2H6.
The molar mass of the compound is 298 g/mol. To find the molecular formula, we need to calculate the molar mass of Cs and O; Cs has a molar mass of approximately 132.91 g/mol, and O has a molar mass of approximately 16 g/mol. Using these values, we can determine that the compound's molecular formula is Cs11O11.
C5h10
c3h6
The notation "gmol⁻¹" refers to grams per mole, which is a unit of measurement used in chemistry to express the molar mass of a substance. It indicates how many grams of a substance are contained in one mole of that substance. For example, if a compound has a molar mass of 18 gmol⁻¹, it means that one mole of that compound weighs 18 grams. This unit is essential for converting between the mass of a substance and the amount of substance in moles.
The empirical formula of SN has a formula unit mass of the sum of the gram atomic masses of nitrogen and sulfur, i.e., about 46.0667. The gram molecular mass given in the problem divided by this formula unit mass is about 4. Therefore, the molecular formula is S4N4.
Molar Mass
True ~e2020~ BigShawn
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
Molarity is the number of moles of solute per liter of solution, while molar mass is the mass of one mole of a substance. These two concepts are related because the molarity of a compound can be calculated using its molar mass. Molarity is calculated by dividing the number of moles of solute by the volume of the solution in liters.