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510 g Al2S3 is equal to 3,396 moles.

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How many moles of Al2S3 are in 100 g of Al2S3?

100/150.158 is 0.666 moles


How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?

The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )


What is the number of moles of argon in 607 g of argon?

the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles


How is a number of moles of an element determined from a known mass?

The number of moles is mass in g/molar mass in g.


If you have g of beryllium how many moles is this equivalent to?

The formula is: number of moles = g Be/9,012.


What is the number of moles in 0.025 g NH42Cr2O7?

The number of moles 9,92.10e-5.


What is the number of moles in 15 g of As H3?

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How many moles of SO2 are present in 250.0 g?

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.


What is the number of moles if you have 22.99 g of C28H44O?

22.99 g of C28H44O is equal to 0,058 moles.


How many moles are in 4.5 g of AgNO3?

To find the number of moles in 4.5 g of AgNO3, you first need to determine the molar mass of AgNO3 which is 169.87 g/mol. Then you can use the formula: moles = mass / molar mass. Therefore, moles = 4.5 g / 169.87 g/mol ≈ 0.0265 moles.


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Find the number of moles in 607 g krypton?

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