The number of moles in 432 g Mg (OH)2 is 7,407.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
To find the number of moles of magnesium, we first need to calculate the molar mass of magnesium, which is 24.305 g/mol. Next, we convert the mass of the strip to moles using the formula moles = mass/molar mass. Plugging in the values, the number of moles of magnesium in the strip is 0.00463 moles.
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
To find the number of moles, you first need to convert 29.4 mg of BrI to grams by dividing by 1000 to get 0.0294 g. Next, calculate the number of moles by dividing the mass in grams by the molar mass of BrI (which is 207.8 g/mol). Therefore, there are approximately 0.000141 moles of BrI in 29.4 mg.
8,23.1023 atoms Mg is equivalent to 1,366 moles.
The atomic weight of magnesium is 24.31; therefore, the number of moles in 100 gm is 100/24.31 = 4.11, to the justified number of significant digits.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
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To find the number of moles of magnesium, we first need to calculate the molar mass of magnesium, which is 24.305 g/mol. Next, we convert the mass of the strip to moles using the formula moles = mass/molar mass. Plugging in the values, the number of moles of magnesium in the strip is 0.00463 moles.
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
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For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg
To find the number of moles, you first need to convert 29.4 mg of BrI to grams by dividing by 1000 to get 0.0294 g. Next, calculate the number of moles by dividing the mass in grams by the molar mass of BrI (which is 207.8 g/mol). Therefore, there are approximately 0.000141 moles of BrI in 29.4 mg.
Use the formulae n=m/M Where, n - number of mols m - mass M - molar mass Molar mass of Mg = 24 n=202/24 = 8.416
1 mole Mg = 6.022 x 1023 atoms Mg 12.04 x 1023 atoms Mg x 1mol Mg/6.022 x 1023 atoms Mg = 1.999 moles Mg
8,23.1023 atoms Mg is equivalent to 1,366 moles.