The answer is o,5 mol.
8.20g of carbon monoxide, how many grams of methanol will be produced?
The equation for the reaction is 4 Na + O2 -> 2 Na2O. This shows that, for complete reaction, one mole of oxygen is required for each four gram atomic masses of sodium. The gram atomic mass of sodium is 22.9898; therefore, 46 grams of sodium constitutes 2.00 moles of sodium, to more than the justified number of significant digits. The gram molecular mass of diatomic oxygen is 31.9988; therefore 160 grams of oxygen constitutes 5.000 moles of diatomic oxygen, to more than the justified number of significant digits. This is well over the minimum amount of oxygen required for complete reaction of all the sodium present. Each two gram atomic masses of sodium produces one gram formula mass of sodium oxide; therefore, the number of gram formula masses of sodium oxide produced is 1.00, to at least the justified number of significant digits.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.
No, the number of atoms in a substance is determined by Avogadro's number (6.022 x 10^23 atoms/mol). To calculate the number of atoms, you need to convert the mass of each element to moles first using their respective molar masses, which are 22.99 g/mol for sodium and 238.03 g/mol for uranium.
75 g sodium chloride contain 29,75 g sodium.
When sodium reacts with chlorine gas in a 1:1 molar ratio, the resulting compound is table salt (sodium chloride). The molar mass of sodium chloride is approximately 58.5 g/mol. Therefore, when you combine 1.5 grams of chlorine gas with sodium, you would produce approximately 58.5 grams of table salt.
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
Using stoichiometry, we can calculate that 27 grams of sodium metal reacting with water produces 40 grams of sodium hydroxide. Since 40 grams of sodium hydroxide were produced, this correlates to 27 grams of sodium being consumed. Therefore, the water added should be the difference between the initial weight of sodium (27 grams) and the weight of sodium left (0 grams) after the reaction, resulting in 27 grams of water being added.
155.2 g
The gram atomic mass of sodium is 22.9898, the formula of the least hydrated form of sodium phosphate is Na3PO4.10 H2O, and the gram formula unit mass of this sodium phosphate is 344.09. Therefore, the mass fraction of sodium in this sodium phosphate is 3(22.9898)/344.09 or about 0.20044, and the grams of sodium in 7.2 grams of this sodium phosphate is 1.44 grams of sodium, to the justified number of significant digits.
To find the maximum number of grams of silver that can be produced, first calculate the moles of copper and silver nitrate using their respective molar masses. Then, determine the limiting reactant using the stoichiometry of the reaction. Finally, calculate the maximum number of grams of silver that can be produced by multiplying the moles of silver obtained from the limiting reactant by the molar mass of silver.
When 42.0 grams of baking soda (sodium bicarbonate, NaHCO3) decomposes, it produces 22.0 grams of sodium carbonate (Na2CO3) and 20.0 grams of carbon dioxide (CO2) gas.
The molar mass of sodium is 22.99 g/mol. To find the total number of sodium atoms in 46.0 grams of sodium, you would first convert grams to moles using the molar mass, then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms. This would give you approximately 1.21 x 10^24 sodium atoms.
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
Balanced equation. 2Na + Cl2 >> 2NaCl 46 grams sodium = 2 mol 23 grams Chlorine = 0.65 mol ( I think Chlorine is limiting ) 0.65 mol Cl (2mol Na/1mol Cl ) = 1.3 mol ( you do not have that; Cl limits ) 0.65 mol Cl (2mol NaCl/1mol Cl2 )(58.44g/1mol NaCl ) = 75.9 grams