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What is the overall voltage for the non-spontaneous redox reaction involving mg and cu and their ions?
In a redox reaction involving magnesium (Mg) and copper ions (Cu²⁺), magnesium is oxidized and copper is reduced. The standard reduction potential for Cu²⁺ to Cu is +0.34 V, while the standard reduction potential for Mg²⁺ to Mg is -2.37 V. The overall cell voltage (E°) for the reaction is calculated as the difference between these potentials: E° = E°(reduction) - E°(oxidation) = 0.34 V - (-2.37 V) = +2.71 V. Since this voltage is positive, the reaction is spontaneous under standard conditions, contrary to the premise of being non-spontaneous.
What is the overall voltage for the nonspountanious redox reaction involving Mg and Cu and their ions?
In the nonspontaneous redox reaction involving magnesium (Mg) and copper (Cu), the overall voltage (or electromotive force, EMF) can be determined using standard reduction potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall voltage for the reaction, calculated by subtracting the reduction potential of magnesium from that of copper, is approximately +2.73 V. However, since the reaction is nonspontaneous, the voltage indicates that an external energy source is required to drive the reaction.
How can a galvanic cell become electrolytic cell?
A galvanic cell can become an electrolytic cell by applying an external voltage that is of opposite polarity to the cell's spontaneous voltage. This external voltage can overcome the natural tendency of the cell to generate electricity and drive a non-spontaneous chemical reaction in the reverse direction, converting it into an electrolytic cell.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
What is the voltage of this reaction Fe3 e----- Fe 2 Cu---- Cu2 2e?
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
What is the overall voltage for the non-spontaneous redox reaction involving mg and cu and their ions?
In a redox reaction involving magnesium (Mg) and copper ions (Cu²⁺), magnesium is oxidized and copper is reduced. The standard reduction potential for Cu²⁺ to Cu is +0.34 V, while the standard reduction potential for Mg²⁺ to Mg is -2.37 V. The overall cell voltage (E°) for the reaction is calculated as the difference between these potentials: E° = E°(reduction) - E°(oxidation) = 0.34 V - (-2.37 V) = +2.71 V. Since this voltage is positive, the reaction is spontaneous under standard conditions, contrary to the premise of being non-spontaneous.
What is the overall voltage for the non spontaneous redox reaction involving Mg and Cu and their irons?
The overall voltage for the non-spontaneous redox reaction between Mg and Cu can be calculated by finding the difference in standard reduction potentials between the two half-reactions. The standard reduction potentials for Mg and Cu are -2.37 V and 0.34 V, respectively. Therefore, the overall voltage would be (-2.37 V) - (0.34 V) = -2.71 V.
What is the overall voltage for the nonspountanious redox reaction involving Mg and Cu and their ions?
In the nonspontaneous redox reaction involving magnesium (Mg) and copper (Cu), the overall voltage (or electromotive force, EMF) can be determined using standard reduction potentials. The standard reduction potential for Cu²⁺/Cu is +0.34 V, while for Mg²⁺/Mg it is -2.37 V. The overall voltage for the reaction, calculated by subtracting the reduction potential of magnesium from that of copper, is approximately +2.73 V. However, since the reaction is nonspontaneous, the voltage indicates that an external energy source is required to drive the reaction.
What does a positive cell voltage mean?
The reaction is spontaneous.
What is the overall voltage for the nonspontaneous redox reaction involving mg and cu and their ions?
-2.37 - 0.34
What is the voltage for the non spontaneous reaction between silver Ag and copper Cu and their ions?
The standard cell potential for the non-spontaneous reaction between silver and copper ions (Ag+ and Cu2+) is determined by subtracting the reduction potential of Ag+ from that of Cu2+. The cell potential would be negative as the reaction is non-spontaneous, indicating that an external voltage larger than the calculated value would be needed to drive the reaction in the reverse direction.
How can a galvanic cell become electrolytic cell?
A galvanic cell can become an electrolytic cell by applying an external voltage that is of opposite polarity to the cell's spontaneous voltage. This external voltage can overcome the natural tendency of the cell to generate electricity and drive a non-spontaneous chemical reaction in the reverse direction, converting it into an electrolytic cell.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag s and Cu s Cu2 2e?
The overall voltage for the redox reaction involving Ag and Cu is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode. Given the reduction potentials of Ag and Cu as 0.80 V and 0.34 V respectively, the overall voltage is 0.46 V, calculated as (0.34 V) - (0.80 V).
What is the voltage of this reaction Fe3 e----- Fe 2 Cu---- Cu2 2e?
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
What is the overall voltage for a redox reaction with the half reactions Ag e Ag and Cu2 2e?
0.80-0.34
What is the overall voltage for the nonspontaneous redox reduction involving Mg and Cu and their ions?
The overall voltage for the nonspontaneous redox reaction involving magnesium (Mg) and copper (Cu) can be determined using standard reduction potentials. The reduction potential for Cu²⁺ to Cu is +0.34 V, while the oxidation potential for Mg to Mg²⁺ is -2.37 V. The overall cell potential (E°cell) is calculated by adding the reduction potential of the cathode (Cu) to the oxidation potential of the anode (Mg), resulting in E°cell = 0.34 V - 2.37 V = -2.03 V. Since the value is negative, the reaction is nonspontaneous under standard conditions.
Non-spontaneous reaction be in an electrolytic cell?
A non-spontaneous reaction occurs in an electrolytic cell where an external voltage is applied to drive a chemical reaction that would not occur naturally. In this setup, electrical energy is converted into chemical energy, facilitating processes like electrolysis. For example, the decomposition of water into hydrogen and oxygen gases requires an electrolytic cell to supply the necessary energy to overcome the activation barrier. Overall, electrolytic cells are crucial in various applications, including metal plating and the production of chemical compounds.
