An acidic solution will have a pOH ranging from 7 to 14
pH + pOH =14
3
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.
To find the pOH of a solution, you can use the relationship between pH and pOH, which is given by the equation: pH + pOH = 14. If the pH of the solution is 6.2, then the pOH can be calculated as follows: pOH = 14 - pH = 14 - 6.2 = 7.8. Therefore, the pOH of the solution is 7.8.
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the hydroxide ion concentration [OH⁻] is 9.0 × 10⁻⁷ M, the pOH can be calculated as follows: pOH = -log(9.0 × 10⁻⁷) ≈ 6.05. Thus, the pOH of the solution is approximately 6.05.
Yes it is possible. For bases the pH values generally range over 7 to 14. Alternatively pOH can be used, where pH + pOH = 14.
pH + pOH =14
The pOH is 6,4.
To calculate the pH of an acid or base, use the formula pH = -log[H+], where [H+] is the hydrogen ion concentration in moles per liter. To find the hydrogen ion concentration, use the equation [H+] = 10^(-pH). For bases, you can use the pOH = -log[OH-] formula to calculate the pOH, then find the hydroxide ion concentration with [OH-] = 10^(-pOH).
It will have a pOH of 12. Because pH+pOH=14
1.8
The pOH is 8,7.
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Poh Poh could be the sound a pogo stick makes with each jump, or it could be the sound made by a dyslexic bunny.
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
10.7(pH) - 14 = 3.3 (pOH)
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4