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What is the percent composition by mass of iron in iron (III) chloride?
To calculate the percent composition by mass of iron in iron (III) chloride (FeCl₃), first determine its molar mass. The molar mass of Fe is approximately 55.85 g/mol, and for Cl, it is about 35.45 g/mol, giving FeCl₃ a total molar mass of approximately 162.2 g/mol (55.85 + 3 × 35.45). The percent composition of iron is then calculated as (mass of Fe / molar mass of FeCl₃) × 100, which is (55.85 / 162.2) × 100 ≈ 34.4%. Thus, the percent composition by mass of iron in iron (III) chloride is approximately 34.4%.
What the percent composition of Pb and Fe in galena?
Galena is primarily made up of lead (PbS) and iron. The percent composition of lead (Pb) in galena is typically around 86.6%, while the percent composition of iron (Fe) is very low, usually less than 1%.
What is the chemical composition for grade ggg40 ductile iron?
Percent by weight: Carbon (C) 3.70, Silicon (Si) 2.50, Manganese (Mn) 0.40 The rest is iron (Fe)
What is the atomic mass of Fe?
The atomic mass of iron (Fe) is approximately 55.85 grams per mole.
How many moles are in 23 g of Fe?
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
What is the percent composition of FeO?
FeO is 50 mole % Fe and 50 mole % O FeO is 77.73 mass % Fe and 22.27 mass % O mass fraction X = molar mass X / (total molar mass of compound) mass % Fe = [atomic mass Fe] / ([atomic mass Fe] + [atomic mass O])
What is the percent composition by mass of iron in iron (III) chloride?
To calculate the percent composition by mass of iron in iron (III) chloride (FeCl₃), first determine its molar mass. The molar mass of Fe is approximately 55.85 g/mol, and for Cl, it is about 35.45 g/mol, giving FeCl₃ a total molar mass of approximately 162.2 g/mol (55.85 + 3 × 35.45). The percent composition of iron is then calculated as (mass of Fe / molar mass of FeCl₃) × 100, which is (55.85 / 162.2) × 100 ≈ 34.4%. Thus, the percent composition by mass of iron in iron (III) chloride is approximately 34.4%.
What the percent composition of Pb and Fe in galena?
Galena is primarily made up of lead (PbS) and iron. The percent composition of lead (Pb) in galena is typically around 86.6%, while the percent composition of iron (Fe) is very low, usually less than 1%.
If weight percent of Fe is 69.96 percent what is the mass of Fe in 25.0 grams?
25.0 g x 69.96% = 17.49 g
How many percent composition of barium nitrate?
Barium nitrate consists of one barium cation (Ba2+) and two nitrate anions (NO3-). The percent composition can be calculated by finding the molar mass of each element in the compound and dividing by the molar mass of the whole compound. For barium nitrate (Ba(NO3)2), the percent composition of barium is approximately 20.6% (Ba: 137.33 g/mol, Ba(NO3)2: 261.34 g/mol).
What is the percent of iron in iron (II) hydroxide?
Iron (II) hydroxide has a chemical formula Fe(OH)2. To find the percent of iron in iron (II) hydroxide, you need to calculate the molar mass of iron (Fe) and divide it by the molar mass of the compound Fe(OH)2, then multiply by 100 to get the percentage. The percent of iron in iron (II) hydroxide is approximately 69.9%.
What is the mass in grams in 1.00 molar mass FE?
What is the chemical 'FE'. Do you mean 'Fe'. If so to answer your question . The molar mass of iron (Fe) is 55.845
What is the percent of ferric oxide?
Ferric oxide often refers to iron (III) oxide, which has a chemical formula Fe2O3. The atomic mass of iron (Fe) is 55.85 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Therefore, the molar mass of Fe2O3 is 159.69 g/mol. To calculate the percentage composition of iron (III) oxide, divide the atomic mass of iron by the molar mass of the compound and multiply by 100. So, (2 * 55.85) / 159.69 ≈ 0.698 or 69.8% is the percent of ferric oxide.
What is the empirical formula of an iron oxide that 65.0 percent fe and 35.0 percent O?
The empirical formula of the iron oxide compound is Fe₂O₃. This is determined by dividing the percentage of each element by its molar mass to find the ratio of atoms in the compound.
What is the percent yield for iron if the reaction of 65.0 g of iron(III) oxide produces 42.0g of iron?
The molar mass of Fe2O3 is 159.69 g/mol, and the molar mass of Fe is 55.85 g/mol. Theoretical yield of Fe = (42.0 g Fe) / (55.85 g/mol) x 2 = 1.50 mol Fe. Percent yield = (actual yield / theoretical yield) x 100 = (42.0 g / 1.50 mol x 55.85 g/mol) x 100 = 63.2%.
What is a chemical composition of a peridot?
[Mg,Fe]2SiO4
What is the chemical composition for grade ggg40 ductile iron?
Percent by weight: Carbon (C) 3.70, Silicon (Si) 2.50, Manganese (Mn) 0.40 The rest is iron (Fe)
