In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).
2Fe+3Cl2------>2FeCl3
In the reactant aluminum phosphate (AlPO₄), there is one oxygen atom per formula unit. Since there are two formula units of AlPO₄ in the balanced reaction (2AlPO₄), the total number of oxygen atoms is 2 × 4 = 8 oxygen atoms.
The reactants are C8H18 and oxygen.
2Al(NO3)3 + Ca3(PO4)2 -----> 3Ca(NO3)2 + 2Al(PO4)
2Al + 3Cl2 ---> 2AlCl3
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In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).
moles of Al=4.40 g/26.9815 g/mol=0.163 moles cl2=15.4g/70.906g/mol=0.217 the ratio is 2:3 cl2 is the limiting reagent
2Al + 3Cl2 -> 2AlCl3
The equation for the formation of aluminum chloride from its elements is: 2Al(s) + 3Cl2(g) -> 2AlCl3(s)
2Al + 3Cl2 -> 2AlCl3 aluminium reacts with chlorine gas to form aluminium trichloride.
2Al(s) + 3Cl2(g) -> 2AlCl3(s)
2Fe+3Cl2------>2FeCl3
To find the limiting reactant, calculate the moles of each reactant using their molar masses. The balanced chemical equation is 2Al + 3Cl2 → 2AlCl3, so the stoichiometry ratio is 2:3. Aluminum is the limiting reactant as it forms fewer moles of product. Thus, all 25.0 g of aluminum will react with 112.5 g of chlorine to form 67.5 g of aluminum chloride.
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
2i + 3cl2 --> 2icl3