Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol).
Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
no evaporation is vaporization and boiling
Yes boiling is the same thing as vaporizing. This is when a liquid state changes into a gas.
There is no relationship between heat of fusion and heat of vapourisation
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
In SI units: kJ/kmol
The heat of fusion is the amount of heat (not temperature) required to change a solid to a liquid. It is also known as the melting point. The heat of vaporization is the amount of heat (not temperature) required to change a liquid to it's gaseous state. It is also know as it's boiling point.
When liquid molecules absorb enough heat energy, evaporation occurs.
It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.
The latent heat of evaporation
There is no relationship between heat of fusion and heat of vapourisation
molar heat of fusion
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
In SI units: kJ/kmol
both the heat of fusion and the heat of vaporization
The scientific name for ice forming is "freezing" or "solidification." The scientific name for ice melting is "melting" or "fusion."
First things first: it's actually spelled "enthalpy", which might be why you're not finding it.If you want a number, you will need to specify a substance.If you just want to know what it means, then in simple terms it's the amount of energy required to evaporate one mole of the substance.
4.931 kj/mol
The heat of fusion is the amount of heat (not temperature) required to change a solid to a liquid. It is also known as the melting point. The heat of vaporization is the amount of heat (not temperature) required to change a liquid to it's gaseous state. It is also know as it's boiling point.
Latent heat is the amount of thermal energy required to change the phase of a substance. Latent heat of fusion is the amount of energy needed to change it from a solid to liquid or a liquid to solid, and the latent heat of vaporization is the thermal energy needed to change from a liquid to gas or a gas to liquid. For example, in the equation Q = mL, Lfusion (latent heat of fusion) for water is 75.5 cal/gram. Lvaporization (latent heat of vaporization) for water is 539 cal/gram. Substances have different latent heats.