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In SI units: kJ/kmol

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What is the relation of the molar heat of fusion to the molar heat of vaporization?

Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).


What is the heat of what energy needed for a substance to change from a liquid state to an gaseous state?

The quantity of heat required to change the temperature of 1g of a substance by 1 celsius is defined as its specific heat or specific heat capacity.Translating the question into "math-speak" will give you the units: it wants to know heat per gram per degree celsius.Heat = J (or cal), per means divide, gram = g, degree celsius = oC, soJ/(g)(oC), which is the unit for specific heat capacity!


When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?

Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.


what is molar heat capacity and its units?

Molar heat capacity is the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius (or one Kelvin). It is an important thermodynamic property that reflects how a substance absorbs heat. The units of molar heat capacity are typically expressed in joules per mole per degree Celsius (J/mol·°C) or joules per mole per Kelvin (J/mol·K).


What is the energy needed for a substance to change from liquid state to a gaseous state?

thermol

Related Questions

The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?

It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.


Estimate the molar heat of vaporization of a liquid whose vapor pressure doubles when the temperature is raised from 85 C to 95 C?

The molar heat of vaporization can be estimated by using the Clausius-Clapeyron equation, which relates the vapor pressure of a substance to its temperature and molar heat of vaporization. By knowing the temperature change and the corresponding increase in vapor pressure, calculations can be made to determine the molar heat of vaporization.


What is the relation of the molar heat of fusion to the molar heat of vaporization?

Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).


How much heat is absorbed when 75 g of liquid carbon tetrachloride (CCl4) vaporizes into a gas?

The heat absorbed during vaporization is called the heat of vaporization. For carbon tetrachloride, the heat of vaporization is 30.5 kJ/mol. To calculate the heat absorbed when 75 g of CCl4 vaporizes, you would first convert grams to moles using the molar mass of CCl4. Then, use the heat of vaporization to calculate the total heat absorbed.


The amount of energy needed to change a material from a solid to a liquid is the heat of what?

The latent heat of evaporation


What is the heat of what energy needed for a substance to change from a liquid state to an gaseous state?

The quantity of heat required to change the temperature of 1g of a substance by 1 celsius is defined as its specific heat or specific heat capacity.Translating the question into "math-speak" will give you the units: it wants to know heat per gram per degree celsius.Heat = J (or cal), per means divide, gram = g, degree celsius = oC, soJ/(g)(oC), which is the unit for specific heat capacity!


When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?

Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.


How many kilojoules of heat are absorbed when 0.38 g of chloroethane (C2H5Cl bp 12.3 and degC) vaporizes at its normal boiling point (The molar heat of vaporization of chloroethane is 26.4 kJmol.)?

First, calculate the number of moles of C2H5Cl in 0.38 g. Then, use the molar heat of vaporization to find the heat absorbed for this number of moles. Finally, convert the heat from per mole to kilojoules. The heat absorbed when 0.38 g of chloroethane vaporizes at its boiling point will be 3.58 kJ.


What is the amount of energy required to change a material from a liquid to a gas?

Latent Heat of Evaporation, or Evaporation Enthalpy. It is given in units of energy over unit of mass, i.e., KJ/Kg.


How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point?

The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.


What is the heat of vaporation of water?

Vaporization heat of water: 40.65 kJ/mol or 2257 kJ/kg or 539.423 calories per gram (very outdated units!)


What is called to the amount of energy needed to melt one mol a substance?

First things first: it's actually spelled "enthalpy", which might be why you're not finding it.If you want a number, you will need to specify a substance.If you just want to know what it means, then in simple terms it's the amount of energy required to evaporate one mole of the substance.