To determine the temperature change when 40g of ice is added to 100g of water at room temperature, you must consider the heat transfer involved in melting the ice and warming the resulting water. The heat absorbed by the ice to melt (latent heat of fusion) and then raise its temperature to the final equilibrium temperature will lead to a decrease in the temperature of the warm water. The final temperature will depend on the initial temperature of the water and the specific heat capacity of both water and ice, which typically results in a lower equilibrium temperature than the initial temperature of the water.
Substances with a low specific heat capacity will experience the greatest increase in temperature when 100g of heat is added. This means that metals like copper or aluminum, which have low specific heat capacities, will increase in temperature the most compared to substances like water or sand which have higher specific heat capacities.
NaNO3 at 10C = About 80g KNO3 at 60C = About 100g NaCl at 50C = About 38g
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
Short answer: 2kcalTo be preceise, it depends on the temperature of the water, because the heat capacity of a substance changes with temperature. But in a practical sense, that doesn't matter, because the change is usually very small.If we know the definition of a calorie, it's actually quite easy to calculate this. 1 calorie is the amount of energy required to increase the temperature of 1g of water by 1C. What we need to do is just play with the definition so that it fits with our numbers. So to raise 100g of water with 20C, we need 1cal*C-1*g-1*100g*20C = 2000 cal = 2 kcal (1 kcal = 1 kilocalorie = 1000 cal)
~ 6.3 kilojoules When 1 g of water is cooled down by 1°C it releases 1 calorie so cooling 100g of water 15 times 1°C releases 1500 calories worth of heat. The transfer factor from calorie to joule is ~ 4.2 joules/calorie 1500 calories * 4.2 joules/calorie = 6300 joules = 6.3 kilojoules
Burning 100g of water at 100 degrees would release more energy than burning 100g of steam at 100 degrees, as water at a higher temperature has more thermal energy to be released. Burning water at 100 degrees would first need to raise its temperature to its boiling point before converting it into steam.
Substances with a low specific heat capacity will experience the greatest increase in temperature when 100g of heat is added. This means that metals like copper or aluminum, which have low specific heat capacities, will increase in temperature the most compared to substances like water or sand which have higher specific heat capacities.
Very simply 1g of ammonium thiocyanate and 100g (100ml) of water!
Assuming the solid is the limiting reagent, the saturation point of the solution is reached when no more solid can dissolve in the solvent, creating a saturated solution. The solubility of the solid must be known to determine if 40g can fully dissolve in 100g of water.
100g
100g
100g of water is equal to 100g of ice in terms of weight, since they both have the same mass. However, the volume of the ice may be slightly larger due to the lower density of ice compared to water.
6.276 kJ
100g
100g
NaNO3 at 10C = About 80g KNO3 at 60C = About 100g NaCl at 50C = About 38g
6.276 kJ