We know that sodium is atomic number 11, and it has 11 protons, 11 electrons (in a neutral atom), and will have 12 neutrons in its sodium-23 isotope. Sulfur is atomic number 16, and will have 16 protons, 16 electrons (in a neutral atom), and will have 16 neutrons in it sulfur-32 isotope. Oxygen has atomic number 8, and has 8 protons, 8 electrons (in a neutral atom) and will have 8 neutrons in its oxygen 16 isotope. If we take 2 sodium atoms, a sulfur atom and 4 oxygen atoms, we'll have a total of 70 protons, 72 neutrons and 70 electrons in sum.
Na2SO4 is not a molecular formula because it represents an ionic compound, sodium sulfate. In ionic compounds, the elements are held together by ionic bonds rather than sharing electrons in covalent bonds like in molecular compounds. The formula Na2SO4 indicates that there are two sodium ions (Na+) for every sulfate ion (SO4^2-).
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq).
To find the number of protons in Na2SO4, we first need to determine the atomic structure of the elements present. Na (sodium) has 11 protons in each atom, sulfur (S) has 16 protons, and oxygen (O) has 8 protons. In Na2SO4, there are 2 sodium atoms, 1 sulfur atom, and 4 oxygen atoms. Therefore, the total number of protons in Na2SO4 can be calculated as 2(11) + 1(16) + 4(8) = 50 protons.
Na2SO4 is not a molecular formula because it represents an ionic compound, sodium sulfate. In ionic compounds, the elements are held together by ionic bonds rather than sharing electrons in covalent bonds like in molecular compounds. The formula Na2SO4 indicates that there are two sodium ions (Na+) for every sulfate ion (SO4^2-).
Sulfate consists of 1 S, and 4 O and so has a charge of 2-. You can see this directly from the periodic table by checking what group these atoms are in. Sulfur and Oxygen are both in the 6th group, meaning they both have 6 valence electrons. So (6 electrons * 5 atoms) = 30 electrons. If we follow the octet rule (each atom must have 8 valence electrons for a full octet), then we need 2 more electrons. Sodium, Na, is in the 1st group on the periodic table, and therefore has 1 valence electron. So we need 2 sodium atoms, giving us the formula: Na2SO4 That is, 2 Na 1 S 4 O It's important to remember that when atoms 'share' their electrons by bonding, that BOTH atoms 'see' the electrons as theirs, meaning that, for example, although you may have 14 electrons between 2 atoms, as long as there is a single bond between the atoms they will both have full octets. For example: O2 :::O:O::: where : = pair of electrons.
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
Na2SO4 is an ionic compound because it is composed of a metal (Na) and a nonmetal (S and O). Ionic compounds form when metal atoms transfer electrons to nonmetal atoms, resulting in the formation of positively and negatively charged ions that are held together by electrostatic forces.
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
1 mol Na2SO4 will dissociate to 2 mol Na+ and 1 mol SO42- Therefore 0.350 M Na2SO4 will dissociate to 0.350*2 = 0.700 mol Na+ and 0.350*1 = 0.350 mol SO42- Therefore the total concentration of ions is 0.700 mol + 0.350 mol = 1.050 mol.
Sodium sulfate.
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).
When Na2SO4 dissolves in water, it dissociates into two Na+ ions and one SO4 2- ion. The dissociation equation is: Na2SO4 (s) -> 2Na+ (aq) + SO4 2- (aq).
The chemical formula for sodium sulfate is Na2SO4.