The volume is 3,81 L.
This is another calculation. there are 0.123 moles inn this volume.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
Pressure, volume and temperature, and moles of gas are the four principal variables to describe a gas (for example, see related questions on Ideal Gas Law and others). The standard units are: Pressure: atmospheres (atm) Volume: liters (L) Temperature: Kelvin (K) Number of moles are measure in, well, moles.
ATM (atmosphere) is a unit of pressure measurement. It is commonly used to express atmospheric pressure, where 1 ATM is equivalent to the average pressure at sea level. Therefore, ATM is not a measurement of volume or temperature.
The answer is 0,125 moles.
38 L
This is another calculation. there are 0.123 moles inn this volume.
You can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
A. An increase in pressure from 2 ATM to 3 ATM will result in a decrease in volume of gas. B. An increase in pressure from 3 ATM to 4 ATM will result in a decrease in volume of gas. C. A decrease in pressure from 4 ATM to 1 ATM will result in an increase in volume of gas. D. An increase in pressure from 1 ATM to 3 ATM will result in a decrease in volume of gas.
38 L
Using the ideal gas law, V = (nRT)/(P), where n = moles, R = gas constant, T = temperature in Kelvin, and P = pressure in atm. Plug in the values to find the volume: V = (2.00 moles * 0.0821 L.atm/mol.K * 300 K) / (2.62 atm) = 49.22 L. Therefore, 2.00 moles of hydrogen gas at 2.62 ATM and 300.C will occupy 49.22 liters of volume.
Pressure, volume and temperature, and moles of gas are the four principal variables to describe a gas (for example, see related questions on Ideal Gas Law and others). The standard units are: Pressure: atmospheres (atm) Volume: liters (L) Temperature: Kelvin (K) Number of moles are measure in, well, moles.
The total moles of gas in the mixture is 0.220 + 0.350 + 0.640 = 1.210 moles. To find the pressure of H2, we need to consider the mole fraction of H2, which is 0.350/1.210 = 0.289. So, the pressure of H2 is 0.289 * 2.95 Atm = 0.852 Atm.
The total moles of gas in the container is 9 moles (5 moles CO2 + 3 moles N2 + 1 mole H2). To find the partial pressure of CO2, divide the moles of CO2 by the total moles of gas and multiply by the total pressure: (5 moles CO2 / 9 moles total gas) * 1.05 ATM = 0.5833 ATM. Therefore, the partial pressure of CO2 in the container is 0.5833 ATM.
38 L
0.125 moles
The answer is 0,125 moles.