To determine the mass of ice that can be melted by 2.0 kJ of energy, we use the latent heat of fusion for ice, which is approximately 334 J/g. First, convert 2.0 kJ to joules (2.0 kJ = 2000 J). Then, divide the total energy by the latent heat: ( \frac{2000 , \text{J}}{334 , \text{J/g}} \approx 5.99 , \text{g} ). Thus, about 6 grams of ice can be melted by 2.0 kJ of energy.
Ice storms happens when a cold mass of air and a warm mass of air combine to create a ice storm
To determine how much heat a 20 kg block of ice absorbs as it melts, we need to use the formula ( Q = m \cdot L_f ), where ( Q ) is the heat absorbed, ( m ) is the mass of the ice, and ( L_f ) is the latent heat of fusion for ice, approximately 334,000 J/kg. Thus, for a 20 kg block of ice, the heat absorbed would be ( Q = 20 , \text{kg} \cdot 334,000 , \text{J/kg} = 6,680,000 , \text{J} ) or 6.68 MJ. This is the amount of heat required to completely melt the ice at 0°C.
The final temperature of the liquid water after all the ice has melted will be 20 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the water in cooling down from 60°C to the final temperature is equal to the heat gained by the ice in melting and then heating up to 20°C.
Ice. For 6 gr of water and 8 deg C you need 6 x 8 = 48 calories For 5 gr of ice and 20 deg C you need at least 100 ( 5 x 20) if we neglect small difference in the specific heat of ice versus water. If the ice melts then you need additional thermal energy to break the hydrogen bonds in ice (melting thermal energy) so it is even more.
force = mass x acceleration force = mass x (distance/sec2) force x distance = mass x (distance2/sec2) force x distance= work done (energy) energy = mass x velocity2 10km/h = 10000m/h = 166and 2/3 m/s energy as ball hits person on ice = 20 x 166.672 = 555577.778Joules now energy is neither created nor destroyed it is simlply transferred from one form to another assuming ice has no friction then 555577.778= newmass x velocity2 velocity2 = 555577.778/80 = 6944.722225 velocity = 83.335m/s = 5000.1m/h = 5km/h
The heat absorbed by the ice can be calculated using the formula Q = m * L, where Q is the heat absorbed, m is the mass of the ice (20 kg), and L is the latent heat of fusion for ice (334 kJ/kg). Therefore, the ice absorbed 20 kg * 334 kJ/kg = 6680 kJ of heat as it melted.
1. Ice sheets contain enormous quantities of frozen water. If the Greenland Ice Sheet melted, scientists estimate that sea level would rise about 6 meters (20 feet). If the Antarctic Ice Sheet melted, sea level would rise by about 60 meters (200 feet). 2. The Antarctic and Greenland ice sheets contain more than 99 percent of the freshwater ice on Earth. 3. An ice sheet is a mass of glacial land ice extending more than 50,000 square kilometers (20,000 square miles).
Ice storms happens when a cold mass of air and a warm mass of air combine to create a ice storm
There is no mass loss (nor gain) in state change, so there would be 100 grams of ice formed.
To determine how much heat a 20 kg block of ice absorbs as it melts, we need to use the formula ( Q = m \cdot L_f ), where ( Q ) is the heat absorbed, ( m ) is the mass of the ice, and ( L_f ) is the latent heat of fusion for ice, approximately 334,000 J/kg. Thus, for a 20 kg block of ice, the heat absorbed would be ( Q = 20 , \text{kg} \cdot 334,000 , \text{J/kg} = 6,680,000 , \text{J} ) or 6.68 MJ. This is the amount of heat required to completely melt the ice at 0°C.
The final temperature of the liquid water after all the ice has melted will be 20 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the water in cooling down from 60°C to the final temperature is equal to the heat gained by the ice in melting and then heating up to 20°C.
You can tell if ice cubes have reached room temperature by observing if they have completely melted. Once they have melted, the water will reach room temperature. Placing a thermometer in the water can also confirm if it has reached room temperature.
6,660,000 J
Ice has a density of 916,8 kilograms per cubic meter or 0.9128 grams per cubic centimeter. 20 cubic meters of ice weigh then 20 times 916,8 = 18336 kilograms = 18.336 tonnes.
From a macroscopic standpoint When you add heat to the water/ice mixture the water will warm up a little bit. The warmer water melts a little ice, and the latent heat of the ice absorbs the extra heat. From a microscopic standpoint The slightly warmer (faster) water molecules bump into the ice, which knocks a few molecules off. The formerly frozen molecules have lower kinetic energy, so the average kinetic energy of the water drops back to the melting point of the ice.
The thermal power required can be calculated using the formula: Power = (mass * specific heat capacity * change in temperature) / time. Given data: mass = 2.5kg, specific heat capacity of ice = 2100 J/kg°C, specific heat capacity of water = 4200 J/kg°C, change in temperature = 20°C, and time = 2 minutes. First calculate the energy required to melt the ice (from -10°C to 0°C), then to heat the water to 20°C. Finally, divide the total energy by the time in seconds to get the thermal power.
First you need to know at what temp. is the ice?The latent heat of fusion for ice at 32 degrees F is 144 but per pound.This will change 1 pound of ice at 32 degrees F into water at 32 degrees F.It is defined as the amount of heat required for the 1 mole of ice to bring a change in its state, that is, from solid state to liquid state. It is also known as enthalpy of fusion, specific melting point or latent heat of fusion of ice. The particular temperature at which there is a change in the state of the ice is known as the melting point of ice.