Yes iron is more reactive than copper because it is higher up on the activity series. There is more reasons to back this up such as outer electrons more tightly bound than others. Those who have less tightly bound electrons are more reactive. Hope this helps you. :D
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
Copper (Cu) does not form more than one type of cation.
When iron (Fe) reacts with copper oxide (CuO), it forms iron oxide (Fe2O3) and copper (Cu). This reaction is a displacement reaction where the more reactive iron displaces copper from copper oxide.
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
3 types, Cu (Copper), Fe (Iron) and S(Sulfur)
Copper (Cu) is more active than nickel (Ni) and less active than zinc (Zn).
How well it can replace other metals in a reaction. For example iron is more active than copper, because CuSO4 + Fe --> FeSO4 + Cu reaction occurs. And Cu + FeSO4 --> no reaction
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
Fe + Cu(NO3)2 --> Fe(No3)2 + Cu
The balanced chemical equation for the reaction of iron (Fe) with copper (Cu) is: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Copper (Cu) does not form more than one type of cation.
When iron (Fe) reacts with copper oxide (CuO), it forms iron oxide (Fe2O3) and copper (Cu). This reaction is a displacement reaction where the more reactive iron displaces copper from copper oxide.
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
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Cu (copper) is a more noble metal than Fe (iron)
The formula for iron is Fe. The formula for copper sulfate is CuSO4. The chemical equation for the reaction is Fe (s) + CuSO4 (aq) --------- Cu (s) + FeSO4(aq) The iron is a more active metal than copper therefore it replaces the copper in the copper sulfate solution.
Hg, Cu, Fe, W