The balanced equation for the reaction between potassium chlorate (KClO3) and potassium chloride (KCl) in the presence of oxygen (O2) typically represents a decomposition reaction. However, KClO3 can decompose into KCl and O2 when heated. The balanced equation for this decomposition is: 2 KClO3 → 2 KCl + 3 O2.
This is a decomposition reaction. The compound potassium chlorate (KClO3) breaks down into potassium chloride (KCl) and oxygen gas (O2) when sulfur (S) is heated.
The reaction between H2SO3 and KClO3 does not occur. H2SO3 is a weak acid, and KClO3 is a salt. There is no precipitation, gas evolution, or significant heat release that would indicate a chemical reaction taking place between these two substances.
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
When KClO3 is heated in the presence of MnO2, it undergoes a decomposition reaction to produce potassium chloride (KCl) and oxygen gas (O2). The manganese dioxide (MnO2) acts as a catalyst, speeding up the reaction but remains unchanged itself.
This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
This chemical reaction is known as a decomposition reaction, where a single compound breaks down into two or more simpler substances. In this case, potassium chlorate (KClO3) decomposes into potassium chloride (KCl) and oxygen gas (O2).
This is a decomposition reaction. The compound potassium chlorate (KClO3) breaks down into potassium chloride (KCl) and oxygen gas (O2) when sulfur (S) is heated.
The reaction between H2SO3 and KClO3 does not occur. H2SO3 is a weak acid, and KClO3 is a salt. There is no precipitation, gas evolution, or significant heat release that would indicate a chemical reaction taking place between these two substances.
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
This reaction is:2 KClO3 = 3 O2 + 2 KCl
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
O2 is oxygen molecule; KCl is potassium chloride
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).