well..... the liquid will turn more alkaline which means that it will be less reactive. daaa!!! im in yr 8 btw
The rate would quadruple (increase by a factor of 4). This is because the rate depends on the SQUARE of the concentration of NO.
If the concentration of NO was doubled in the rate law rate = k[NO]2[H3], the rate of the reaction would increase by a factor of 4. This is because the rate of a reaction typically increases with an increase in the concentration of reactants, raised to a power dictated by their respective coefficients in the rate law equation.
Increasing the concentration of either SO2 or O2 would drive the reaction towards the formation of more SO3, resulting in an increase in the concentration of SO3. Increasing the temperature, however, would cause the greatest increase in the concentration of SO3 as it favors the forward reaction which produces more SO3.
For a second-order reaction, the rate of reaction is proportional to the square of the concentration of the reactant. Therefore, to achieve a tenfold increase in the reaction rate, the concentration must be increased by a factor of √10 (approximately 3.16). This is because if the concentration is increased by this factor, the rate will increase by (√10)² = 10.
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The rate would quadruple (increase by a factor of 4). This is because the rate depends on the SQUARE of the concentration of NO.
If the concentration of NO was doubled in the rate law rate = k[NO]2[H3], the rate of the reaction would increase by a factor of 4. This is because the rate of a reaction typically increases with an increase in the concentration of reactants, raised to a power dictated by their respective coefficients in the rate law equation.
Increasing the concentration of either SO2 or O2 would drive the reaction towards the formation of more SO3, resulting in an increase in the concentration of SO3. Increasing the temperature, however, would cause the greatest increase in the concentration of SO3 as it favors the forward reaction which produces more SO3.
For a second-order reaction, the rate of reaction is proportional to the square of the concentration of the reactant. Therefore, to achieve a tenfold increase in the reaction rate, the concentration must be increased by a factor of √10 (approximately 3.16). This is because if the concentration is increased by this factor, the rate will increase by (√10)² = 10.
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
For most reactions which involve liquids or gases, increasing the concentration of the reactants also increases the rate of reaction. This is because the number of effective collisions are also increased which speeds up the reaction.
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Increasing the concentration of an acid would increase the rate and vigor of the reaction involving a metal such as magnesium.
increase temperature use a catalyst increase concentration increase surface area of what you are reacting (crushing into a powder)
The rate would be four times larger
All the stupid people would die.
The rate law describes the relationship between the concentration of reactants and the rate of a chemical reaction. Generally, an increase in the concentration of reactants will lead to a proportional increase in the reaction rate if the reaction is first order with respect to that reactant. For example, if the rate law is rate = k[A]^2, doubling the concentration of A would quadruple the reaction rate.