To determine the current when using a 45-ohm bulb, you can apply Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If you know the voltage of the circuit, you can calculate the current by using the formula I = V/R. For example, if the voltage is 120 volts, the current would be I = 120V / 45Ω, resulting in approximately 2.67 amps. Adjust the voltage in the calculation based on your specific scenario to find the current.
Light bulb in the home - alternating current (A/C) Light bulb in a car - direct current (D/C) Output of a battery charger - direct current Input of a battery charger - usually alternating current
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
To find the resistance necessary, one would need to know how much current the bulb draws. If one knows the current the bulb draws, then one would subtract the 14 volts from 120 volts then divide that by the current the bulb draws and one will find the resistance needed. Once this has been done, one would need to multiply the current drawn by the voltage drop to get the wattage rating necessary. Another important detail to note is that the power dissipated by the resistor will be much greater than the power consumed by the bulb itself. Finally if the bulb burns out the voltage across the contacts will be 120V. I would not recommend using this method to drop the voltage for the bulb.
No, a higher wattage INCANDESCENT light bulb uses more current than a lower wattage INCANDESCENT light bulb. Some CF and LED bulbs are rated by the amount of light that an incandescent bulb would produce, but they are also rated by the wattage that they use.
When lighting a light bulb, it is changed into light and heat/thermal energy.
V = irv = (0.5)(250)v = 125
The new bulb has higher resistance than the old one did, and it's designed to use less electrical energy than the old one used.
Light bulb in the home - alternating current (A/C) Light bulb in a car - direct current (D/C) Output of a battery charger - direct current Input of a battery charger - usually alternating current
An example of a parallel circuit would be the light bulbs in track lighting. Each bulb has the same voltage applied. The current through any one light bulb equals the voltage divided by the resistance of the bulb. The current also equals the wattage of the bulb divided by the voltage. So if all the bulbs had exactly the same resistance the current would be the same. However, your question says "always" so in general the answer is no. In the case of track lighting if you had a 60 watt bulb in parallel with a 120 watt bulb, the 60W bulb would draw 1/2 amp and the 120W bulb would draw 1 amp. The sum of the current flowing in a parallel circuit equals the sum of the current in each leg of the circuit.
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
The brightness of a bulb would not change if you added a second bulb in parallel with the first.Unless, of course, the increased current exceeded the power supply's capacity causing a reduction in voltage.
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
A light bulb would act as a load in a circuit. It transforms electrical energy into light energy and heat when current passes through it. It offers resistance to the flow of current, causing it to light up.
If a bulb with higher resistance is used in a simple circuit, the total resistance in the circuit would increase. According to Ohm's Law (V=IR), with an increase in resistance, the current in the circuit would decrease since the voltage supplied remains constant.
To increase the current you either need to reduce the resistance of the load or increase the voltage. Typically a higher wattage light bulb will decrease resistance or you could put multiple batteries in series.
Thomas Edison has changed the world by making the light bulb because............... Maycee Frey