Molality of a solution is defined as the number of gram moles, for molecular compounds, or gram formula unit masses, for ionic compounds, mixed with each kilogram of solvent. Sodium chloride is the solute in the question, and water is the solvent.
Avogadro's Number is defined as the number of formula units required to constitute one gram formula unit and has the value of about 6.022 X 1023. Therefore, 10 formula units of NaCl constitutes 10/(6.022 X 1023) or about 1.6606 X 10-23 gram formula unit.
The gram molecular mass of water is 18.0518. Therefore, 200 molecules of water contains (200)(18.0518)/(6.022 X 1023) or about 599.5 X 10-23 grams or 0.5995 X 10-23) kilograms.
Therefore, the molality of the given mixture is 1.6606/0.59995* or about 2.768.
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*The number 10-23 appears in both numerator and denominator, and therefore need not be included in this fraction.
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
Delta T = imKI = van't Hoff factor = 3 for CaCl2 m = molality = moles solute/kg solvent = ? K = boiling point constant for water = 0.512 Delta T = change in temperature = 4.4 deg C Plug in the values and solve for m
Molality is moles solute per kilograms of solvent, so 2/10=0.2m.
To calculate the total number of atoms in seven molecules of water, you can use the formula: atoms per molecule x number of molecules. In water (H2O), there are 3 atoms per molecule (2 hydrogen atoms and 1 oxygen atom), so for seven molecules, you would have 3 x 7 = 21 atoms.
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
To calculate the molality of a solution, you need to know the moles of solute (in this case, NaCl) and the mass of the solvent (water). First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality using the formula molality = moles of solute / mass of solvent in kg.
To calculate the molality of a solution, you need to divide the moles of the solute (in this case, NaCl) by the mass of the solvent (water) in kilograms. First, convert the mass of NaCl to moles using its molar mass. Then, calculate the molality by dividing the moles of NaCl by the mass of water in kilograms.
Convert the 200 mol of water to kilograms of water.
The molality of a solution is defined as the number of moles of solute per kilogram of solvent. First, convert the grams of water to kilograms. Then, calculate the molality using the formula: molality = moles of acetic acid / kilograms of water.
To calculate the molality of a solution, you need to know the moles of solute and the mass of the solvent in kilograms. First, calculate the moles of NaCl in 0.2 kg: moles = mass (g) / molar mass. Then, calculate the molality by dividing the moles of solute by the mass of solvent in kg: molality = moles of solute / mass of solvent in kg.
To calculate the molality of 10 g of NaCl in 2 kg of water, you need to determine the number of moles of NaCl and the mass of the solvent (water) in kilograms. First, calculate the molar mass of NaCl, which is approximately 58.44 g/mol. Then, divide the mass of NaCl (10 g) by its molar mass to find the number of moles, and finally, use the formula for molality: molality = moles of solute / mass of solvent (in kg). In this case, the calculation would be molality = (10 g / 58.44 g/mol) / 2 kg.
3mol/6kg
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
Convert the 200 mol of water to kilograms of water.
Convert the 200 mol of water to kilograms of water.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
To find the molality, first convert the mass of sucrose to moles by dividing by its molar mass (342.3 g/mol). Then calculate the moles of water in 676g. Finally, divide the moles of sucrose by the kg of water (0.676kg) to get the molality, which would be approximately 0.127 mol/kg.