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When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
Are there specific units you have to use when using the molarity equation?
Yes, when using the molarity equation, the units for concentration must be in moles per liter (mol/L) and for volume must be in liters (L). Ensure that the units of both concentration and volume are consistent to calculate molarity accurately.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
Is seawater passed through sleeves is a solution or heterogeneous mixture?
To be a true solution seawater must be filtered.
When determine the molarity of a solution you must make sure that your answer is in terms of?
mol per dm cube
What is the effect on the molarity of a solution of adding more solvent to a solution?
Adding more solvent to a solution decreases the molarity of the solution. This is based on the principle that initial volume times initial molarity must be equivalent to final volume times final molarity.
How many salt is in a salt solution?
The salt content of a salt solution can be found from the solutions' molarity. Any solution with a salt content can be called a salt solution. There is no one set standard which determines the amount of salt which must be in a solution for it to be a salt solution.
How many grams of sodium sulfate Na's must be added to make 500 ml of M sodium sulfate solution?
To determine the grams of sodium sulfate needed, you first need to specify the molarity (M) of the sodium sulfate solution. Once you have the molarity, you can use the formula: grams = molarity (M) x volume (L) x molar mass (g/mol). This will give you the amount of sodium sulfate in grams needed to make the solution.
How do you make a Molar solution from 32 percent hydrochloric acid?
To make a molar solution from a 32% hydrochloric acid solution, you would need to first calculate the molarity of the 32% solution. Molarity is calculated by multiplying the percent concentration by the density of the solution and dividing by the molar mass of the solute. Once you determine the molarity, you can then dilute the solution to the desired molar concentration by adding the appropriate amount of solvent (usually water).
Approximately how much water must be added to the 3.0 L solution to dilute it to 0.18M?
To dilute a 3.0 L solution to 0.18M, you would need to add approximately 12 L of water to achieve the desired concentration. This is calculated using the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume.
If 1.25 grams of pure CaCO3 required 25.5 mL of a HCl solution for complete reation what is the molarity for the HCl solution?
When calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) the reaction is:- CaCO3 + 2 HCl -> CaCl2 + H2O + CO2 The weight for 1 mole of calcium carbonate is the atomic weight in grams or 40.8 + 12.011 + 3 x 15.9994 = 100.8092 grams 1.25 grams of CaCO3 is therefore 1.25/100.8092 or .0124 mole There must have been twice this many moles of HCl in the solution or 0.0248 mole. The molarity of the solution is the number of moles per litre so with 0.0248 in 25.5 ml there must be .97 mole in 1 litre. The HCl solution must therefore be .97 molar
What is the relationship between Ksp and the product of ion concentrations in terms of determining whether a solution if those ions is saturated?
The relationship is that the product of the ion concentrations must equal the Ksp value for the solution to be saturated. If the product exceeds the Ksp value, then a precipitation reaction will occur until equilibrium is reached. Conversely, if the product is less than the Ksp value, the solution is not saturated and more solute can dissolve.
How many moles of naoh are contained in 65.0ml of a 2.20m solution of naoh in H2O?
Moles/Liters=Molarity (M) therefore: Molarity*Liters=moles Since you were given milliliters, you must first convert your volume to liters for the equation to be accurate. 2.2M*.065L=moles=.143 moles NaOH
A 0.200M solution of sodium carbonate Na2CO3 is made by dissolving 5.30g of the solid in water and making up the mark in a standard flask What volume must the flask be?
To find the volume of the flask, first calculate the moles of Na2CO3 using its molar mass. Then use the molarity and moles to find the volume using the formula Molarity (M) = moles/volume (in liters). The volume of the flask needed is then the inverse of the molarity.
A 2.14-L sample of hydrogen chloride HCl gas at 2.61 ATM and 28C is completely dissolved in 668 mL of water to form hydrochloric acid solution Calculate the molarity of the acid solution Assume n?
Using this ideal gas equation PV=nRT. The question provided the following: P=2.61 atm V=2.14L R=0.0821 ( this is standard for any ideal gas) T= 28 C+273K= 301 n= unknown Since there is no volume change, so the volume is constant from the beginning of the reaction to the the end of the reaction. The only key information we are missing is the actual number of moles (n). We must rearrange the ideal gas equation to solve for moles. n=PV/RT n=(2.61)(2.14)/(.0821)(301) n=.2260 The question wants us to find the Molarity of the acid solution. We were given that HCL completely dissolved in 668mL of water. Molarity moles/Liters. 668mL=.668L M=.2260mol/.668L so Molarity of the acidic solution is .338.
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
