When sodium (Na) bonds with chlorine (Cl), sodium donates one electron to chlorine. As a result, chlorine achieves a stable electron configuration resembling that of the nearest noble gas, argon. Chlorine ends up with a full outer shell containing eight electrons, giving it the electron configuration of (1s^2 2s^2 2p^6), which is characteristic of a stable, anionic form (Cl⁻).
One electron is transferred from each sodium to each chloride.
Sodium (Na) donates an electron, while chlorine (Cl) receives an electron. Sodium has one electron in its outermost shell, which it readily loses to achieve a stable electronic configuration. In contrast, chlorine has seven electrons in its outer shell and needs one more to complete it, making it inclined to accept an electron. This transfer of electrons facilitates the formation of ionic bonds between these two elements.
Chlorine will gain one electron when forming an ion. Chlorine therefore fills its valence electron shell with 8 e-. Chlorine usually bonds with group 1 metals, like Na (Sodium).
Octet configuration refers to how elements generally prefer to form bonds so as to attain an octet configuration, i.e. have 8 electrons in their valence shell. For example, chlorine (Cl) is from Group VII and has 7 valence electrons. It will gain one electron (eg from sodium which loses one electron to form Na+) to form Cl-, which has 8 valence electrons and so fulfills the octet rule and is stable. The electronic configuration of sodium is 2.8.1 (if you're in secondary school), or 1s2,2s2,2p6,3s1 (more advanced). So by losing one electron to form Na+, sodium also attains octet configuration.
In the periodic table, the two members of the atom's family that are considered complete opposites are sodium (Na) and chlorine (Cl). Sodium, a metal, readily loses an electron to achieve a stable configuration, while chlorine, a non-metal, gains an electron to complete its outer shell. This electron transfer leads to the formation of ionic bonds, exemplifying their contrasting chemical behaviors. Together, they form sodium chloride (table salt), showcasing their oppositional yet complementary nature.
Sodium reacts with chlorine gas because sodium wants to donate its electron to chlorine to achieve a stable electron configuration, and chlorine wants to gain an electron to also become stable. This electron transfer results in the formation of ionic bonds between sodium and chlorine atoms, leading to the creation of sodium chloride (table salt).
When sodium bonds with chlorine to form table salt (sodium chloride), the sodium's valence electron is transferred to chlorine. This transfer results in sodium losing one electron to achieve a full outer shell of electrons (achieving a stable electron configuration), while chlorine gains one electron to also achieve a full outer shell. This transfer of electrons creates an ionic bond between the two atoms.
In the reaction with sodium, chlorine gains an electron to achieve a stable electron configuration, forming an ionic bond in sodium chloride. In the reaction with another chlorine atom, they share electrons to achieve a stable electron configuration and form a covalent bond in a chlorine molecule. Both reactions aim to achieve a full outer electron shell and increase stability, but the manner in which electrons are shared or transferred differs based on the type of bond formed.
Sodium has one electron in its outer shell, while chlorine needs one electron to complete its outer shell. When sodium gives away its electron to chlorine, they both achieve a more stable electron configuration, forming an ionic bond.
a. Sodium and chlorine form ionic bonds when combined. Sodium has an extra electron it wants to lose, and chlorine has an extra electron it wants to gain, so they transfer electrons to each other to achieve a stable electron configuration.
Transferred to the chlorine atom, forming Na+ and Cl- ions. This electron transfer results in the formation of ionic bonds between the sodium and chlorine ions, leading to the creation of sodium chloride (table salt).
Sodium (Na) and chlorine (Cl) would form an ionic bond. Sodium tends to lose an electron to achieve a stable electron configuration, while chlorine tends to gain an electron. The resulting ions attract each other due to their opposite charges, forming an ionic bond.
One electron is transferred from each sodium to each chloride.
it is an ionic bond. The sodium donates its one valence electron to Chlorine and results in ionic bond
Ionic bonds form between sodium and chlorine. Sodium will donate its outer electron to chlorine, resulting in the formation of a sodium ion with a +1 charge and a chloride ion with a -1 charge. These ions are held together by strong electrostatic attractions.
Sodium (Na) donates an electron, while chlorine (Cl) receives an electron. Sodium has one electron in its outermost shell, which it readily loses to achieve a stable electronic configuration. In contrast, chlorine has seven electrons in its outer shell and needs one more to complete it, making it inclined to accept an electron. This transfer of electrons facilitates the formation of ionic bonds between these two elements.
Chlorine usually bonds ionically by gaining one electron.