When astatine-218 undergoes alpha decay, it emits a helium nucleus (alpha particle) and transforms into the new element, polonium-214. This process reduces the atomic number of the nucleus by 2 and the mass number by 4.
Bismuth-214 produces Polonium-214 by beta- decay. It also produces Thallium-210 by alpha decay, though at a much smaller percentage.
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
Alpha particle is nothing but the He nucleus. He nucleus has two protons and two neturons. So 4 nucleons. As alpha comes out of the parent nucleus, then the by product ie daughter nucleus would have 2 protons less and 4 nucleons less. So 88Ra226 after emitting one alpha particle gets changed into 86 Rn 222. Rn is Radon. So 88Ra226 ----------> 86 Rn 222 + 2 He 4
bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206
Uranium-235 will not beta decay first. If you google "Chart of Nuclides" you can follow the entire decay chain yourself using each isotope's most likely decay type.
The decay of thorium by alpha decay the resultant nuclide is the element radium. The specific nuclide of radium cannot be determined unless we know which specific nuclide of thorium underwent alpha decay.
Bismuth-214 produces Polonium-214 by beta- decay. It also produces Thallium-210 by alpha decay, though at a much smaller percentage.
When bismuth-212 undergoes alpha decay, it becomes thallium-208.
If seaborgium undergoes alpha decay, it would create rutherfordium as the resulting element.
Alpha particle is nothing but the He nucleus. He nucleus has two protons and two neturons. So 4 nucleons. As alpha comes out of the parent nucleus, then the by product ie daughter nucleus would have 2 protons less and 4 nucleons less. So 88Ra226 after emitting one alpha particle gets changed into 86 Rn 222. Rn is Radon. So 88Ra226 ----------> 86 Rn 222 + 2 He 4
Polonium-218 undergoes alpha decay to form lead-214, which then undergoes beta decay to form bismuth-214.
bismuth 210 decays by beta decay to polonium 210 that decays by alpha decay to lead 206
90Th232 undergoes alpha decay to form 88Ra228. Remember, in alpha decay, a helium nuclei is emitted, comprising two protons and two neutrons. As a result, the atomic number goes down by 2, and the atomic mass number goes down by 4.
Uranium-235 will not beta decay first. If you google "Chart of Nuclides" you can follow the entire decay chain yourself using each isotope's most likely decay type.
When 90Sr undergoes beta decay, it forms 90Y (Yttrium-90). In beta decay, a neutron is converted into a proton, and an electron (beta particle) and an antineutrino are emitted.
When uranium undergoes alpha decay, it emits an alpha particle (which consists of 2 protons and 2 neutrons) and transforms into thorium. The mass of the thorium produced can be determined by subtracting the mass of the emitted alpha particle from the original mass of the uranium nuclide. The specific mass of thorium will depend on the isotope of uranium that is decaying, but it generally corresponds to the mass number of the uranium minus 4 (for the alpha particle).
Uranium 238 is transformed in thorium 234 by alpha decay.