In order to find information on NaHC03, it would probably be best to get a college level science or chemistry book from your local college library or book store.
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 is commonly called bicarbonate of soda or baking soda.
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NaHCO3 is the chemical formula f sodium bicarbonate.Carbon is here tetravalent.
The ratio of NaHCO3 to WHAT!
To find the percent composition of NaHCO3 in a sample, you would calculate the mass of NaHCO3 in the sample divided by the total mass of the sample, then multiply by 100 to get the percentage.
The balanced chemical equation for the breakdown of sodium bicarbonate (NaHCO3) is: 2 NaHCO3 -> Na2CO3 + CO2 + H2O From this equation, it can be seen that one mole of NaHCO3 produces one mole of H2O. The molar mass of NaHCO3 is 84 g/mol. Therefore, 168 g of NaHCO3 will produce 84 g of H2O.
To find the moles of NaCl formed from NaHCO3, we need to consider the stoichiometry of the reaction. The balanced equation is: 2 NaHCO3 -> Na2CO3 + H2O + CO2 Therefore, for every 2 moles of NaHCO3, we get 1 mole of NaCl. Therefore, 3.25 moles of NaHCO3 would produce 1.625 moles of NaCl.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
To find the moles of NaHCO3 in a 3.00 g sample, first calculate the molar mass of NaHCO3 (84.01 g/mol). Then, divide the mass of the sample by the molar mass to obtain the moles of NaHCO3. For this sample, 3.00 g / 84.01 g/mol ≈ 0.036 moles of NaHCO3 are present.
NaHCO3 has a total of 6 atoms - one sodium (Na), one hydrogen (H), one carbon (C), and three oxygen (O) atoms.
The answer is NaHCO3
To find the mass of C6H8O7 needed to consume 0.42g of NaHCO3, you first need to balance the chemical equation for the reaction between them. Then, calculate the molar ratio between NaHCO3 and C6H8O7 to determine the mass needed. This involves stoichiometry and molar mass calculations to find the answer.
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
Which items are you asking about? This a chemical compound and it has 2 sodium, 2 hydrogen, 2 carbon, and 6 oxygen atoms.
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