Neon is larger because it has more protons, electrons, and neutrons. Look at the element's Atomic Mass for an idea of its size.
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
To calculate the number of gram atoms in 22.4 liters of helium, we first need to convert the volume to moles using the ideal gas law. Since helium is a monoatomic gas, 1 mole of helium is equivalent to 4 grams (its molar mass). Therefore, the number of gram atoms in 22.4 liters of helium would be 22.4 liters * (1 mole / 22.4 liters) * (4 grams / 1 mole) = 4 grams.
I won't even waste the time looking up actual numbers.a mole of atoms of helium is about 4 grams, therefor 1 gram of helium is about 0.25 moles of helium atomsa mole of atoms of uranium is about 238 grams, therefor 1 gram of uranium is about 0.0042 moles of uranium atomsA gram of helium contains more atoms than a gram of uranium by about a factor of 60.
The lead atom is way heavier than the helium atom. We know this by referring to the Periodic Table of Elements. The atomic mass of lead (Pb) is 207, while that of helium (He) is 4. Therefore, we can estimate that an atom of lead is about 50 times heavier than an atom of helium.
.7 g= .17 mol = 1.05 x 10^23 atoms
A gram atomic mass of helium (He) contains the same number of atoms as 1 mole of helium. Since 1 mole of any substance contains approximately 6.022 x 10^23 atoms, a sample of helium with a gram atomic mass would contain that same number of atoms.
To calculate the number of gram atoms in 22.4 liters of helium, we first need to convert the volume to moles using the ideal gas law. Since helium is a monoatomic gas, 1 mole of helium is equivalent to 4 grams (its molar mass). Therefore, the number of gram atoms in 22.4 liters of helium would be 22.4 liters * (1 mole / 22.4 liters) * (4 grams / 1 mole) = 4 grams.
I won't even waste the time looking up actual numbers.a mole of atoms of helium is about 4 grams, therefor 1 gram of helium is about 0.25 moles of helium atomsa mole of atoms of uranium is about 238 grams, therefor 1 gram of uranium is about 0.0042 moles of uranium atomsA gram of helium contains more atoms than a gram of uranium by about a factor of 60.
520 kg = 5.20 X 105 grams. The gram atomic mass of helium is 4.0026; therefore the number of moles of helium in 520 kg is (5.20/4.0026) X 105 or 1.30 X 105. Multiplying this number by Avogadro's Number, 6.022 X 1023, yields the number of atoms, which is about 7.82 X 1028, to the justified number of significant digits.
The lead atom is way heavier than the helium atom. We know this by referring to the Periodic Table of Elements. The atomic mass of lead (Pb) is 207, while that of helium (He) is 4. Therefore, we can estimate that an atom of lead is about 50 times heavier than an atom of helium.
.7 g= .17 mol = 1.05 x 10^23 atoms
The answer is 4,745.10e21 atoms.
There are approximately 6.022 x 10^22 atoms in 1 gram of sulfur based on Avogadro's number, which is the number of atoms or molecules in one mole of a substance.
The element helium does not technically have "moles", because its atomsdo not form any chemical bond with other helium atoms. Its formula unit is a single atom. Avogadro's Number, the number of formula units in a gram atomic mass, is about 6.022 X 1023. Therefore, 1.20 x 1025 atoms constitutes (1.20 X 1025)/(6.022 X 1023) or about 19.9 formula masses, to the justified number of significant digits.
No, even a small 1 gram sample of iron contains a very large number of iron atoms. Iron has a molar mass of 55.85 g/mol, so 1 gram of iron would contain about ( \frac{1}{55.85} ) moles of iron atoms, which is approximately ( 6 \times 10^{22} ) atoms.
32 g
To work this out you need to know the atomic weight of calcium and Avogadros number, which is the number of atoms in a gram atom. Calcium has an atomic weight of 40.078. Therefore a gram ato is 40.078 grams which contains 6.02214129(27)×1023 atoms. 1g of calcium contains 6.02214129(27)×1023 / 40.078 1.502 X 1022