A binary compound consists of two different elements. Among the given options, NaOH (sodium hydroxide) is not a binary compound because it contains three different elements: sodium (Na), oxygen (O), and hydrogen (H). The other compounds (NaCl, H2O, and CH4) each consist of only two elements.
The compound that contains carbon is CH₄, which is methane. It consists of one carbon atom bonded to four hydrogen atoms. NaCl (sodium chloride) and Ca (calcium) do not contain carbon.
The equation for the reactions of the carboxylic acids with NaOh is COOH + NaOH --------> CH 3 COONa + H 2 O. Sodium acetate and water are the products formed.
The name of this compound is 2-chlorobutane.
CH compound does not exist. So it has no bonds.
No, methyl chloride is considered to be organic.
1. CH is an organic radical. 2. NaCl is an inorganic compound.
The compound CH-O-CH-CH-CH is an ether, which is a type of organic compound containing an oxygen atom bonded to two carbon atoms in an alkyl chain. Ethers are characterized by the -O- functional group.
The equation for the reactions of the carboxylic acids with NaOh is COOH + NaOH --------> CH 3 COONa + H 2 O. Sodium acetate and water are the products formed.
First you need the formula for the two starting ingredients. Sodium hydroxide is NaOH and Tartaric acid is HOOC--CH(OH)--CH(OH)--COOH. This can be found by looking at for example, the related link. Other searches will show that NaOH reacts with a carboxylic acid thus: -----COOH + NaOH -----> COONa +H2O in general terms. So putting all this information together we know that 2 molecules of NaOH will be needed per molecule of tartaric acid. So the final reaction equation is HOOC-CH(OH)-CH(OH)-COOH +2NaOH ----> NaOOC-CH(OH)-CH(OH)-COONa + 2H20
You think probable to cycloocta-1,5-diene.
The name of this compound is 2-chlorobutane.
CH compound does not exist. So it has no bonds.
crotonaldhyde CH3-CH=CH-CHO
R 1 O --(CH 2 --CH(OR 2)--CH 2 O)n--R 3 (II)
The reaction between 2-iodohexane and sodium methoxide will result in the substitution of the iodine atom by the methoxy group. The product formed will be 2-methoxyhexane. The equation for the reaction is 2-iodohexane + sodium methoxide -> 2-methoxyhexane + sodium iodide.
Alcohol is the after product of bacteria eating sugar. The first step is to obtain a good source of sugar. This is usually from a plant or grain. Then it is worked on by the yeast and the results can be distilled to make liquor.
Polystyrene is definitely a compound. It is addition polymer compound. As a compound it is and alkene (ethene) with a phenyl group in place of one of the hydrogens. H2C = CH ){Phenyl) The alkene bond opens and polymerises (chaions up) with another alkene bond. -H2C-CH(Ph) -CH2- CH(Ph) -