There is this special thing where you can get it lazared away and it atays gone forever and it doesn't hurt i had it done on my lip
To determine the genotype of a white ram, breed him with black females. Black females are homozygous recesive for the black trait, a. If the ram is homozygous dominant, all offspring will be white (and heterozygous). If the ram is heterozygous, approximately half of it's offspring will be white and half will be black.
The probable phenotype of the offspring would be black, as black color is dominant over chestnut color. The genotype of the offspring would be heterozygous for black (Bb), since one parent is homozygous black (BB) and the other is homozygous chestnut (bb).
A test cross with a homozygous recessive guinea pig (bb) would reveal the genotype of the black guinea pig. If all offspring are black, then the black guinea pig is most likely homozygous dominant (BB). If both black and white offspring are produced, then the black guinea pig is likely heterozygous (Bb).
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
here is my answer found using a Punnett Square: for one trait (lets use hair color) both guinea pigs are hazel. But, because they are heterozygous they also have the resessive gene for white. So, you cross Hh with Hh. You then have this genotypic ratio: 1 HH:2 Hh:1 hh This can be translated into a phenotypic ratio: 3 hazel: 1 white The final answer: You will have 25% homozygous dominant, 50% heterozygous (showing the dominant), and 25% homozygous recessive.
There are a couple possibilities, depending on the genetic makeup of the horses. First, a few definitions: homozygous for black means the horse has two genes for the color black. This horse can only pass on a black gene. Heterozygous for black - the horse has one gene for black, and one for chestnut. Either one can be passed on. The horse will appear black, though can produce chestnut foals. If they are both homozygous for black the foal will be black, and will be homozygous for black. If one of them is homozygous and the other heterozygous, you will always have a black foal, but there is a 50/50 chance of being homozygous for black. If both of them are heterozygous, you have a 25% chance of getting a chestnut, 50% chance of getting a heterozygous black, and 25% change of a homozygous black.
Black coat homozygous: BB Black Coat heterozgous: Bb
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
They refer to the alleles in a genotype. For the basics of genetics, we can say that each allele is either dominant or recessive. Dominant is represented by an uppercase letter, and recessive a lowercase. If the genotype is AA, it is homozygous dominant. If it is aa it is homozygous recessive. If it is Aa, it is heterozygous. Simply, homozygous means that both of the alleles are the same and heterozygous means it has one of each allele.
The genotype of a male solid black rabbit is likely to be either homozygous (BB) or heterozygous (Bb) for the black coat color gene, where "B" represents the dominant allele for black fur and "b" represents the recessive allele for other colors. If the rabbit is homozygous (BB), it carries two copies of the black allele. If it is heterozygous (Bb), it still exhibits the black coat color due to the dominance of the "B" allele.
To determine the genotype of a white ram, breed him with black females. Black females are homozygous recesive for the black trait, a. If the ram is homozygous dominant, all offspring will be white (and heterozygous). If the ram is heterozygous, approximately half of it's offspring will be white and half will be black.
To determine the hair color of the guinea pigs' offspring, we need to know the genotypes of the parents. If one parent is homozygous dominant (BB) and the other is homozygous recessive (bb), all offspring will be heterozygous (Bb) and will have black hair. If both parents are heterozygous (Bb), approximately 25% of the offspring are expected to be homozygous dominant (BB), 50% heterozygous (Bb), and 25% homozygous recessive (bb), resulting in a 75% chance of black hair and a 25% chance of white hair.
Two cows cannot mate to get a calf (or "cow" in this instance). You have to have a BULL and a cow to get a baby calf. Just like you gotta have a Mom and a Dad to "make" you.Now back to the question. If the bull is black and the cow is black, there is a high chance that you will get a black calf. However, let's increase the complexity and throw in a bit of genetic terminology in here.Let B = black and b = red. Black is always homozygous or dominant to red in cattle.If both the sire and dam is heterozygous black (Bb x Bb) , there is a 25% chance that you will get a red calf (bb). But if both parents are homozygous for black, there is a 100% chance that the calf will not be red, but instead, homozygous black (BB). If either one of the parents are heterozygous black, the calf still has a 100% chance that it will be black, phenotypically. But, genotypically, the calf has a 25% chance of being heterozygous black. A heterozygous black calf, no matter if it grows into a cow or a bull (depending on the calf's sex), will have a 25% chance of giving birth to or siring red calves if crossed with a heterozygous black bull or cow or a a 75% chance of siring a red calf with a red bull or cow.
The answer below should be that they will all be black: the last portion is right (3 homo. black to 1 het. black) but all the mice will have black coats. 3 black to 1 white, ......B equals black, w equals white, 3homozygous black to 1 heterozygous black.
To determine if a black guinea pig is homozygous or heterozygous for black fur, you would need to cross it with a white guinea pig. If the offspring are all black, then the black guinea pig is homozygous. If any white offspring are produced, then the black guinea pig is heterozygous.
The probable phenotype of the offspring would be black, as black color is dominant over chestnut color. The genotype of the offspring would be heterozygous for black (Bb), since one parent is homozygous black (BB) and the other is homozygous chestnut (bb).
If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.