If the radius is larger, the surface will also be larger. As a functional dependency, you only need one - the radius, or the surface - whatever.
Both the absorption and the luminosity of a blackbody in equilibrium increase in magnitude with increasing temperature, and the spectral distribution of the luminosity increases in frequency (decreases in wavelength).
In that case, both the star's diameter and its luminosity greatly increase.
Through a comparison of solar luminosity and temperature seen with the H-R diagram. On this diagram, stars sharing the same temperature but different luminosities show measurable differences in radius as well as mass. So if two stars both have the same visible surface temperature but one is more luminous, it has to be larger. This is further explained by Stefan Boltzmann's law,L=(4πR^2 x sigma(constant) x T^4)A Star with the the same surface temperature with larger surface area results in more Luminosity.
Most visual binary stars are of low luminosity because they are often close together and both stars have similar masses, resulting in them being fainter than single stars of the same age. Additionally, the companion stars in these binary systems may not be large or hot enough to emit high levels of light.
These are both direct relationships, so yes.KE = mv2PE = mghAs you see, both depend on mass. ( unless they are set to equal )
The bigger the star's radius, the greater its surface area which emits the light. The bigger the temperature, the more luminous is the light the star is emitting.
As temperature decreases, luminosity will also decrease As radius increases (and with it surface area, but radius is a much easier to work with if you're trying to compare stars so we usually say radius) luminosity will also increase. If both are happening at the same time, it is possible that the luminosity of the star will remain more or less constant. Often one change will dominate the other, such as when a star goes through the red giant phase when the increase in radius has a far greater effect than the drop in temperature, and the star becomes more luminous.
Both the absorption and the luminosity of a blackbody in equilibrium increase in magnitude with increasing temperature, and the spectral distribution of the luminosity increases in frequency (decreases in wavelength).
As gravity collapses the cloud to form a protostar, the temperature and luminosity both increase. The increase in temperature is due to the compression of material, causing the protostar to heat up as energy is released. The increase in luminosity is a result of the protostar radiating this energy.
Sirius A and Procyon A are two stars that have similar luminosity and surface temperature. They are both main-sequence stars and are relatively close to each other in terms of these characteristics.
If a star has a large luminosity and a low surface temperature, it must have a large surface area to compensate for the low temperature and still emit a high amount of energy. This would make the star a red supergiant, a type of star that is both luminous and cool at the same time.
Pi*6 * * * * * Independent of the radius? Makes no difference if the disc is twice as wide? I think not! It is actually 2*pi*r2 where r is the radius of the disc.
They both have the same effect on the surface area of the pipe, but the radius has more effect on its volume/capacity.
They both depend on circumference not perimeter.
615.7522 square inches for 1 surface but it will be 1231.5044 for both surfaces
In that case, both the star's diameter and its luminosity greatly increase.
If the radius and height of a cylinder are both doubled, then its surface area becomes 4 times what it was originally, and its volume becomes 8 times as much.