AlBr3 is the product thus:
2 Al + 3 Br2 ------> 2 AlBr3
Aluminum has the anion charge of 3+ and a bromine atom has just 1+ thus you need 3 bromine atoms in order to make the product and end up with a non-charged molecule. Unfortunately bromine comes in its diatomic (two of the same atom) in this equation thus you can't have 1.5 of those molecules. If you multiply in such a way, in this case by two, to make everything whole numbers you have your equation.
The chemical equation is:2 Al(OH)3 = Al2O3 + 3 H2O
Your unbalanced equation is _Al + _Cr2O3 ----> _Cr + _Al2O3. Multiply aluminum (Al) and chromium (Cr) ratio by 2, so each side has the same amount of each element. As a result, the equation 2Al + Cr2O3 -----> 2Cr + Al2O3 is balanced. This is a single replacement reaction.
you take the mass of Al plus three Br. (27.0) + 3(80.0) the answer is 267.
To balance the unbalanced chemical equation involving aluminum oxide (Al₂O₃), you need to ensure that the number of atoms of each element is the same on both sides of the equation. Without the specific equation provided, I can't give the exact coefficient for Al₂O₃. However, in typical reactions involving Al₂O₃, the coefficient could vary based on the reactants and products involved. Once the equation is balanced, you would determine the coefficient for Al₂O₃ from that specific context.
To balance the equation Al + Fe3N2 -> AlN + Fe, you need to make sure that the number of each type of atom is the same on both sides of the equation. First, balance the Al by putting a coefficient of 2 in front of AlN to match the 2 Al atoms in Fe3N2. Next, balance the Fe by putting a 3 in front of Fe on the product side to match the 3 Fe atoms in Fe3N2. The balanced equation is: 2Al + 3Fe3N2 -> 2AlN + 9Fe.
The balanced chemical equation for this reaction is: 2KBr + Al(NO3)3 → 2KNO3 + AlBr3
The balanced equation is 3 Fe3O4 + 8 Al -> 4 Al2O3 + 9 Fe. Therefore, the coefficient of Fe is 9.
the answer is 2 apex
This equation is not balanced as given. To balance it, you need to change the coefficients of the reactants and products. The balanced equation is 4Al + 3O2 -> 2Al2O3.
The balanced equation should be 2Al + 6HCl -> 2AlCl3 + 3H2. Therefore, the coefficient of HCl is 6.
In the reaction Al3 Br2 -> 2 AlBr3, aluminum (Al) is oxidized from 0 to +3 (loses electrons) as it goes from Al3 to AlBr3. Bromine (Br) is reduced from 0 to -1 (gains electrons) as it goes from Br2 to AlBr3.
To determine the coefficient of Al in a balanced chemical equation, you would need to provide the specific equation you are referring to. Once you provide the equation, we can help you identify the coefficient of Al in that particular chemical reaction.
You need 4Al and 3O2 This will give you 2 Al2O3
The balanced chemical equation for the reaction is: 3FeO4 + 8Al -> 4Al2O3 + 3Fe Therefore, the coefficient of Fe is 3.
2
The balanced equation is Al(OH)3 + 3HCl ==> 3H2O + AlCl3
Al(NO3)3, so aluminium has coefficient of one. Aluminium is always Al3+ in ionic compounds.