Because it takes no work to bring a test charge in from infinity along the
perpendicular bisector of the dipole (any line in the equatorial plane).
At least, that's true for any distance that's much greater than the separation
of the two charges that make up the dipole. In that case, the potential is
proportional to cos(angle between the line joining the charges and the direction
from its midpoint to the test charge). That's the angle that's 90 degrees in the
equatorial plane, and its cosine is zero.
Dipole-dipole interactions are of electrostatic nature.
In rotating a dipole from stable to unstable equilibrium, the work done is equal to the change in potential energy. As the dipole is moved, the electrostatic potential energy of the system changes, resulting in work being performed on the dipole. The amount of work done is equal to the difference in potential energy between the two equilibrium positions.
It experiences a torque but no force. As the dipole is placed at an angle to the direction of a uniform electric field it experiences two opposite and equal forces which are not along the same line. This develops a torque which aligns the dipole along the field. The dipole does not experience any force as the two forces cancel each other.
in magnetic relays
When molecules are close together, a slight attraction can develop between the oppositely charged regions of nearby molecules. Apex------They form temporary, weak dipole attractions between molecules.
Q1:How to calculate electric potential due to a dipole? Q2:How to calculate electric potential due to ring of charges? Q3:How to calculate electric potential due to charge disk? Q4:how to calculate electric potential due to a quadrupole?
Dipole-dipole interactions are of electrostatic nature.
The angle between the electric dipole moment and the electric field strength on the axial line is 0 degrees (or parallel). This is because on the axial line, the electric field points in the same direction as the electric dipole moment, resulting in the minimum potential energy configuration for the dipole.
No work is done in moving a test charge along the equatorial axis of an electric dipole because the force acting on the charge is perpendicular to the direction of motion. As a result, the work done by the electric field is zero because the force and displacement are orthogonal.
The electric field produced by a dipole at a distance is given by the formula E = 2kP/r^3, where k is the electrostatic constant, P is the dipole moment, and r is the distance from the dipole. This electric field exerts a force on a test charge q placed in the field, given by F = qE. Therefore, the force on a charge due to a dipole moment is directly proportional to the dipole moment and the charge, according to these equations.
Dipole-dipole interactions are of electrostatic nature.
In rotating a dipole from stable to unstable equilibrium, the work done is equal to the change in potential energy. As the dipole is moved, the electrostatic potential energy of the system changes, resulting in work being performed on the dipole. The amount of work done is equal to the difference in potential energy between the two equilibrium positions.
when angle 0 b/w dipole moment vector p and electric field vector E is zero then potential energy of dipole, U=-pEcos0 =-pE and torque=pEsin0=0;which means that the electric dipole is in stable equilibrium.
The electric potential due to a charge distribution can be obtained by integrating the electric field over the path from infinity to the point of interest. This is given by the line integral of the electric field, V = -∫ E ⋅ dl. For a dipole, the electric potential can be derived by considering the potential contributions from both the positive and negative charges of the dipole. The expression for the electric potential due to a dipole is given by V = k * p ⋅ r / r^3, where k is the Coulomb constant, p is the dipole moment, r is the position vector pointing from the charge to the observation point, and the dot product signifies the cosine of the angle between p and r.
When an electric dipole is held in a non-uniform electric field, the dipole experiences a net torque causing it to align itself in the direction of the field. The dipole will tend to orient itself with its positive end facing towards the direction of the field and its negative end facing away from it. This alignment leads to a potential energy change in the dipole, with the dipole experiencing a force due to the non-uniform field.
The angle between the dipole moment and the electric field in an electric dipole is 0 degrees or 180 degrees. This means the dipole moment is either aligned with or opposite to the electric field direction.
An electric field parallel to an electric dipole will exert a torque on the dipole, causing it to align with the field. An electric field anti-parallel to an electric dipole will also exert a torque on the dipole, causing it to rotate and align with the field in the opposite direction.