Yes. Carbon dioxide is a carbon compound that is inorganic.
it has carbon in it, and any compound with carbon is organic therefore, it is an organic molecule
The given compounds are methane (CH4), oxygen (O2), carbon dioxide (CO2), and water (H2O). Methane and carbon dioxide are both organic compounds, while oxygen is a diatomic gas, and water is a simple inorganic compound.
Hydrocarbons such as methane burning in oxygen is an example of oxidation and also combustion.
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
They contain carbon, and usually hydrogen. For example, CO2 is not organic, but CH4 is organic.
Yes. Generally, a compound is only organic when it contains both carbon and hydrogen. CH4,CH2OH, etc
it has carbon in it, and any compound with carbon is organic therefore, it is an organic molecule
A binary molecular compound consists of two elements that are covalently bonded. Examples include carbon dioxide (CO2), water (H2O), and methane (CH4).
The given compounds are methane (CH4), oxygen (O2), carbon dioxide (CO2), and water (H2O). Methane and carbon dioxide are both organic compounds, while oxygen is a diatomic gas, and water is a simple inorganic compound.
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
It has carbon and hydrogen.So it a organic compound
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
As carbon and hydrogen are both nonmetals, it is covalent.
co2
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
CH4 is organic compound.It contains Carbon and Hydrogen
The general chemical equation for the complete combustion of a hydrocarbon is: Hydrocarbon + O2 -> CO2 + H2O For example, the combustion of methane (CH4) can be represented as: CH4 + 2O2 -> CO2 + 2H2O